Symbol: Cl
Number of Neutrons: 18
Atomic Number: 17
Melting Point: -100.98 °C (172.17 K, -149.764 °F)
Number of Protons/Electrons: 17
Atomic Mass: 35.4527 amu
We want to solve Q = mcΔT for the liquid water; its change in temperature will tell us the amount of thermal energy that flowed out of the reaction. The specific heat, c, of water is 4.184 J/g °C.
Q = (72.0 g)(4.184 J/g °C)(100 °C - 25 °C) = 22593.6 J
Q ≈ 2.26 × 10⁴ J or 22.6 kJ (three significant figures).
<span>Here's your balanced chemical equation:
Pb(NO3)2</span><span> (aq) + K2SO4 (aq) </span>⇒<span> PbSO4 (s) + 2KNO3 (aq)
Therefore the precipitate formed is </span>lead(II) <span>sulfate.</span>
So,
All you need to do is read the physical states ( ) to determine the answer.
CuCO3 is solid.
HCl is in aqueous solution.
CuCl2 is in aqueous solution.
H2O is liquid.
CO2 is gas.
It is then easy to see that option D is true. CuCO3 is the solid reactant, and CO2 is the gas product.
