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Juli2301 [7.4K]
3 years ago
12

2. The reaction of zinc with nitric acid was carried out in a calorimeter. This reaction caused the temperature

Chemistry
1 answer:
snow_lady [41]3 years ago
3 0

We want to solve Q = mcΔT for the liquid water; its change in temperature will tell us the amount of thermal energy that flowed out of the reaction. The specific heat, c, of water is 4.184 J/g °C.

Q = (72.0 g)(4.184 J/g °C)(100 °C - 25 °C) = 22593.6 J

Q ≈ 2.26 × 10⁴ J or 22.6 kJ (three significant figures).

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2. Because a cumulonimbus cloud is a towering vertical cloud
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3 years ago
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Calculate the density for a rectangular block using the following measurements: Length = 10 cm, Width = 1.1 cm, Height = 15 cm,
Ksivusya [100]

Answer:

0.40 g/cm3

Explanation:

density = mass / volume.

mass = 65.2 grams

volume = 10*1.1*15=165 cm3

so density = 65.2/165=0.40 g/cm3

3 0
3 years ago
1. How many moles of oxygen are made if 12.0 moles of potassium chlorate react?
Alex787 [66]

Answer:

18

Explanation:

12*3=36

36/2=18

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3 0
3 years ago
Please answer!
evablogger [386]
1.) A compound is a substance that originates from two or more separate elements. It shares some similarities with a mixture.

2.) A compound has quite different properties from which it was formed. It also cannot be separated easily. Compounds are formed by chemical reactions.

3.) A pure substance has a constant composition and has consistent properties. It can be a compound or an element, but its composition is constant.

Hope this helps. :)
5 0
3 years ago
48g of 02 produce how many grams of Al2O3
bixtya [17]

Taking into account the reaction stoichiometry,  102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

4 Al + 3 O₂  → 2 Al₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Al: 4 moles
  • O₂: 3 moles
  • Al₂O₃: 2 moles

The molar mass of the compounds is:

  • Al: 27 g/mole
  • O₂: 32 g/mole
  • Al₂O₃: 102 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Al: 4 moles ×27 g/mole= 108 grams
  • O₂: 3 moles ×32 g/mole= 96 grams
  • Al₂O₃: 2 moles ×102 g/mole= 204 grams

<h3>Mass of Al₂O₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 96 grams of O₂ form 204 grams of Al₂O₃, 48 grams of O₂ form how much mass of Al₂O₃?

mass of Al_{2} O_{3} =\frac{48 grams of O_{2} x204 grams of Al_{2} O_{3}}{96 grams of O_{2}}

<u><em>mass of Al₂O₃= 102 grams</em></u>

Finally, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

3 0
2 years ago
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