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3 years ago

Every chlorine atom has

1 answer:

4 0

Symbol: Cl
Number of Neutrons: 18
Atomic Number: 17
Melting Point: -100.98 °C (172.17 K, -149.764 °F)
Number of Protons/Electrons: 17
Atomic Mass: 35.4527 amu

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The process to separate the various components of a liquid mixture is called __.

lidiya [134]

Answer:

,m.m.m.m.m..mm.m.m...........................................

Explanation:

8 0

3 years ago

Hydrogen sulfide gas gives rotten eggs their terrible odor. Hydrogen sulfide burns in air (O2) to produce sulfide dioxide gas an

gizmo_the_mogwai [7]

Answer:

2.07 mol O₂

Explanation:

First we need to write down the species present in the chemical equation, using the information given by the exercise:

H₂S + O₂ → SO₂ + H₂O

However this equation is not balanced, so now we balance it:

2H₂S + 3O₂ → 2SO₂ + 2H₂O

Now we can use the stoichiometric ratio to calculate the moles of oxygen from the moles of sulfide dioxide:

1.38 molSO₂ * $\frac{3molO_{2}}{2molSO_{2}}$ = 2.07 mol O₂

8 0

3 years ago

Is the reaction to produce zinc from zinc sulfide spontaneous under standard conditions? Coupledreaction: ZnS(s) + H2 (g)  Zn(s

finlep [7]

Answer:

The reaction to produce zinc from zinc sulfide is not spontaneous under standard conditions.

Explanation:

Hess's law states: "When one reaction can be expressed as the algebraic sum of others, its heat of reaction is equal to the same algebraic sum of the partial heats of the partial reactions". So Hess's Law is an indirect method of calculating the heat of reaction or enthalpy of reaction when the chemical reaction occurs in one or more than one stage.

Taking into account that ΔG is a state function, which only depends on the initial and final states, its variation in a reaction is calculated by adding the free energies of the reactants and products involved in it when both are in the normal state. That is, at the pressure of 1natm if it is gases or at the concentration of 1 mol / L for substances in liquid solution.

The sum of the fitted equations should give the problem equation. So, if in a "data" reaction a substance is as a reactant and in the reaction that you must obtain is as a product, you must turn the "data" reaction and ΔG will change its sign. In this case, this happen with the reaction 1 (Rxn1):

Rxn1: ZnS (s) → Zn (s) + S (s) ΔG1°= 201.3 kJ

Rxn2: S (s) + H₂ (g) → H₂S (g) ΔG2°= -33.4kJ

Adding both reactions (taking into account that certain substances appear sometimes as a reagent and others as a product, so they are totally eliminated if they appear in the same quantities) you get:

ZnS (s) + H₂ (g) → Zn (s) + H₂S (g)

Adding algebraically ΔG1° and ΔG2° you get:

ΔG°= ΔG1° + ΔG2°

ΔG°= 201.3 kJ - 33.4 kJ

ΔG°= 167.9 kJ

If a chemical reaction proceeds with a ΔG <0 the process is spontaneous. If, on the other hand, ΔG> 0, the reaction is not spontaneous.

Since ΔG>0, the reaction to produce zinc from zinc sulfide is not spontaneous under standard conditions.

6 0

3 years ago

A government laboratory wants to determine whether water in a certain city has any traces of fluoride and whether the concentrat

nexus9112 [7]

Answer: The given sample of water is not safe for drinking.

Explanation:

We are given:

Concentration of fluorine in water recommended = 4.00 ppm

ppm is the amount of solute (in milligrams) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of fluorine in water, we use the equation:

$\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6$

Both the masses are in grams.

We are given:

Mass of fluorine = $0.152mg=0.152\times 10^{-3}g$ (Conversion factor: 1 g = 1000 mg)

Mass of water = 5.00 g

Putting values in above equation, we get:

$\text{ppm of fluorine in water}=\frac{0.152\times 10^{-3}}{5}\times 10^6\\\\\text{ppm of fluorine in water}=30.4$

As, the calculated concentration is greater than the recommended concentration. So, the given sample of water is not safe for drinking.

Hence, the given sample of water is not safe for drinking.

6 0

3 years ago

How much heat is required to change 25.0 g of water from solid to liquid at 0 oC? Water: ΔHfus = 334 J/g; ΔHvap= 2260J/g

xxMikexx [17]

Answer:

The heat required to change 25.0 g of water from solid ice to liquid water at 0°C is 8350 J

Explanation:

The parameters given are

The temperature of the solid water = 0°C

The heat of fusion, = 334 J/g

The heat of vaporization, = 2260 J/g

Mass of the solid water = 25.0 g

We note that the heat required to change a solid to a liquid is the heat of fusion, from which we have the formula for heat fusion is given as follows;

ΔH = m ×

Therefore, we have;

ΔH = 25 g × 334 J/g = 8350 J

Which gives the heat required to change 25.0 g of water from solid ice to liquid water at 0°C as 8350 J.

3 0

3 years ago