What chemical species are produced when borax dissolves in water?

Chemistry

1 answer:

Alika [10]3 years ago

7 0

It hydrolysed to form sodium borate, NaB(OH)4 $NaB(OH)_4$ and boric acid.

<u>Explanation</u>

Borax is an important mineral, boron compound and is a salt of 'boric acid'. The powdered borax consists of soft colourless crystals that will dissolve in water. It is used in many detergents, enamel glazes and cosmetics.

When mixed with water it produces to form an ion known as the borate ion. Thus hydrolysed to form sodium borate, $NaB(OH)_4$ and boric acid that is chemically written as B(OH)3 or $H_3BO_3.$

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topjm [15]

Answer : The number of moles in 369 grams of calcium hydroxide is, 4.98 moles

Explanation : Given,

Mass of calcium hydroxide = 369 g

Molar mass of calcium hydroxide = 74.093 g/mole

Formula used :

$\text{Moles of calcium hydroxide}=\frac{\text{Mass of calcium hydroxide}}{\text{Molar mass of calcium hydroxide}}$

Now put all the given values in this formula, we get the moles of calcium hydroxide.

$\text{Moles of calcium hydroxide}=\frac{369g}{74.093g/mole}=4.98mole$

Therefore, the number of moles in 369 grams of calcium hydroxide is, 4.98 moles

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3 years ago

What would be the total volume of the new solution when it is changed from 0.2 M to 0.04 M?

34kurt

The question is incomplete.

You need two additional data:

1) the original volume
2) what solution you added to change the volume.

This is a molarity problem, so remember molarity definition and formula:

M = n / V in liters: number of moles per liter of solution

To give you the key to answer this kind of questions, supppose the original volumen was 1 ml and that you added only water (solvent).

The original solution was:

V= 1 ml
M = 0.2 M

Using the formula for molarity, M = n / V

n = M×V = 0.2 M × (1 / 10000)l = 0.0002 moles

For the final solution:

n = 0.0002 moles
M = 0.04

From M = n / V ⇒ V = n / M = 0.002 moles / 0.04 M = 0.05 l

Change to ml ⇒ 0.05 l × 1000 ml / l = 50 ml. This would be the answer for the hypothetical problem that I assumed for you.

I hope this gives you all the cues you need to answer similar problems about molarity.

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