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vovikov84 [41]
3 years ago
7

What chemical species are produced when borax dissolves in water?

Chemistry
1 answer:
Alika [10]3 years ago
7 0

It hydrolysed to form sodium borate,  NaB(OH)4NaB(OH)_4 and boric acid.

<u>Explanation</u>

Borax is an important mineral, boron compound and is a salt of 'boric acid'. The powdered borax consists of soft colourless crystals that will dissolve in water. It is used in many detergents, enamel glazes and cosmetics.

When mixed with water it produces to form an ion known as the borate ion. Thus hydrolysed to form sodium borate,NaB(OH)_4 and boric acid that is chemically written as B(OH)3 or H_3BO_3.

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If the concentration of h uons were to decrease what would happen to the oh ions
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Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an
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Explanation:

The given data is as follows.

      T = 120^{o}C = (120 + 273.15)K = 393.15 K,  

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So,            x_{1} = 0.5   and   x_{2} = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

               p^{sat}_{1} (393.15 K) = 9.2 bar

               p^{sat}_{1} (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

                 p_{1} = x_{1} \times p^{sat}_{1}

                            = 0.5 \times 9.2 bar

                             = 4.6 bar

and,           p_{2} = x_{2} \times p^{sat}_{2}

                         = 0.5 \times 10.5 bar

                         = 5.25 bar

Therefore, the bubble pressure will be as follows.

                           P = p_{1} + p_{2}            

                              = 4.6 bar + 5.25 bar

                              = 9.85 bar

Now, we will calculate the vapor composition as follows.

                      y_{1} = \frac{p_{1}}{p}

                                = \frac{4.6}{9.85}

                                = 0.467

and,                y_{2} = \frac{p_{2}}{p}

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                                = 0.527  

Calculate the dew point as follows.

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          \frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}

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                             P = 9.807

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                   x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}

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                    x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{10.5}

                               = 0.467

4 0
4 years ago
How to balance this equation NH4OH+H3PO4=(NH4)3PO4+H2O with explainatio please ​
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Answer:

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Explanation:

This is an acid-base reaction (neutralization): NH4OH is a base, H3PO4 is an acid

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