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kakasveta [241]
3 years ago
9

Algebra 2 please help

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0

Answer:

1. Negative leading coefficient, fifth degree

2. Positive leading coefficient, fourth degree

Step-by-step explanation:

The graph of a polynomial eventually rises or falls depending on its degree and the sign of the leading coefficient (lc = coefficient of term with the highest exponent)

\begin{array}{ccl}\textbf{Degree} & \textbf{Lc} & \textbf{End Behaviour}\\\text{Even} & + & \text{Up on left and right}\\\text{Even} & - & \text{Down on left; up on right}\\\text{Odd} & + & \text{Down on left and right}\\\text{Odd} & - & \text{Up on left; down on right}\\\end{array}

In addition,  

  • the degree is at least  the number of zeros and  
  • at least 1 greater than the number of local extrema ("bumps"), and  
  • a flattened zero or bump (flex point) shows that shows that it is degenerate (occurs multiple times)

Graph 1

Up on left, down on right —  lc is negative; odd degree

Three zeros —  at least third degree

Two bumps —  at least third degree

Flex points — one at the origin: odd degree, so it occurs 3, 5, 7, or more times.

The polynomial has a positive leading coefficient and is probably fifth degree.

An example is the polynomial y = -x⁵ + x³ (Fig.1).

Graph 2

Up on left and right —  lc is positive; even degree

Four zeros —  at least fourth degree

Three bumps —  at least fourth degree

Flex points — none obvious (although they could be present)

The polynomial has a positive leading coefficient and is probably fourth degree.

An example is the polynomial y = x⁴ - x³ - 4x² - 4x (Fig.2).

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Given : A inequality is given to us . The inequality is 19 ≥ t + 18 ≥ 11 .

To Find : The correct option between the given ones . To write the compound inequality with integers .

Solution : The given inequality to us is 19 ≥ t + 18 ≥ 11 . Let's simplify them seperately .

\red{\tt Case\:1}

⇒ 19 ≥ t + 18 .

⇒ t + 18 ≤ 19 .

⇒ t ≤ 19 - 18 .

⇒ t ≤ 1 = 1 ≥ t . ..................(i)

\red{\tt Case\:2}

⇒ t + 18 ≥ 11 .

⇒ t ≥ 11 - 18.

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<u>On</u><u> </u><u>combing</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>&</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>.</u>

\Large\boxed{\green{\bf \red{\longmapsto} 1 \geqslant t \geqslant -7 }}

This means that t is less than or equal to 1 but greater than or equal to (-7) .

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