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sveta [45]
3 years ago
14

When graphed, the circle with equation

Mathematics
1 answer:
Katarina [22]3 years ago
7 0

Answer:

the correct awnser is B

Step-by-step explanation:

It will lie in Quadrants I and IV, having center (5, 0) and radius 3. Complete the squares and get the equation in standard form, (x - 5)2 + y2 = 9.

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Mrs. Vanwhy made a two-way table to show which students made honor roll and which students study a foreign language.
lara31 [8.8K]

Answer:

Its the 2nd table.

7 0
2 years ago
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The height of a triangle is 7 ft more than its base. if the area of the triangle is 30 ft^ what is the lentgh of the base
Dmitriy789 [7]
Since the area of a triangle is in the form
area=0.5(base)(height)
height=base+7
let base=x
area=0.5(x)(7+x)
30=3.5x+0.5x^2
multiply the equation by 2
60=7x+x^2
subtract 60 from both sides
x^2+7x-60=0
(x-5)(x+12)=0
thus  x=5 or x=-12 since we are only considering positive answers
x=-12 is rejected
so base=5 and height=5+7=12
6 0
3 years ago
Which of the following is a good way to quickly determine whether 3/12 and 1/4 are equal​
Novay_Z [31]

Answer: Divide 3 into the numerator and denominator

Step-by-step explanation:

4 0
2 years ago
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On section AB, whose length is 192 cm, take the point C so that AC: CB = 1: 3. The point D is taken on the AC section so that CD
jasenka [17]

Answer:

  • 112 cm

Step-by-step explanation:

<u>Given:</u>

  • AB = 192 cm
  • AC : CB = 1 : 3
  • CD = BC/12
  • The distance between midpoints of AD and CB = x

<u>Find the length of AC and CB:</u>

  • AC + CB = AB
  • AC + 3AC = 192
  • 4AC = 192
  • AC = 192/4
  • AC = 48 cm

<u>Find CB:</u>

  • CB = 3AC = 3*48 = 144 cm

<u>Find the length of CD:</u>

  • CD = BC/12 = 144/12 = 12 cm

<u>Find the length of AD:</u>

  • AD = AC - CD = 48 - 12 = 36 cm

<u>Find the midpoint of AD:</u>

  • m(AD) = 36/2 = 18 cm

<u>Find the midpoint of CB:</u>

  • m(CB) = AC + 1/2CB = 48 + 144/2 = 48 + 82 = 130 cm

<u>Find the distance between the midpoints:</u>

  • x = 130 - 18 = 112 cm
4 0
2 years ago
if f(x)=3/x+2-sqrtx-3 complete the following statement. The domain for f(x) is all real numbers___ than or equal to 3
Stolb23 [73]
The domain of the function is the set of all the values of x that would allow the function to have real values. Since the radicand is x - 3, the value of x cannot be less than 3 because that would make the value of sqrt (x - 3) an imaginary number. Thus, the domain should be all numbers GREATER than or equal to 3.
6 0
3 years ago
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