Step-by-step explanation:
18+ 5(2x + 5) = 12
18 + 10x + 25 = 12
43 + 10x = 12
10x = 12 -43
10x = -31
x = -3.1
Answer:
They will do rounds together again in 11 minutes and 40 seconds.
Step-by-step explanation:
Security A rounds every 2 minutes and 20 seconds in the gate 1.
That is, after 2*60 + 20 = 120 + 20 = 140 seconds.
Security B rounds every 1 minute and 40 seconds in the gate 2.
That is, after 1*60 + 40 = 60 + 40 = 100 seconds.
After how many minutes they will rounds together again?
First, we find this is seconds, which is the least common multiple between 140 and 100. Factoring them by prime factors:
140 - 100|2
70 - 50|2
35 - 25|5
7 - 5|5
7 - 1|7
1 - 1
lcm(140,100) = 2*2*5*5*7 = 700 seconds
They will do rounds together again in 700 seconds, which is 11 minutes and 40 seconds.
Answer:
69.01 m
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you ...
Tan = Opposite/Adjacent
The tangent function is useful for problems like this. Let the height of the spire be represented by h. The distance (d) across the plaza from the first surveyor satisfies the relation ...
tan(50°) = (h -1.65)/d
Rearranging to solve for d, we have ...
d = (h -1.65)/tan(50°)
The distance across the plaza from the second surveyor satisfies the relation ...
tan(30°) = (101.65 -h)/d
Rearranging this, we have ...
d = (101.65 -h)/tan(30°)
Equating these expressions for d, we can solve for h.
(h -1.65)/tan(50°) = (101.65 -h)/tan(30°)
h(1/tan(50°) +1/tan(30°)) = 101.65/tan(30°) +1.65/tan(50°)
We can divide by the coefficient of h and simplify to get ...
h = (101.65·tan(50°) +1.65·tan(30°))/(tan(30°) +tan(50°))
h ≈ 69.0148 ≈ 69.01 . . . . meters
The tip of the spire is 69.01 m above the plaza.
It is hard to see the picture.
Answer:
5/10 and .5
Step-by-step explanation:
50/100 is 1/2 so 1/2 is equal to 5/10
5/10 is also 1/2 and 1/2 as a decimal is .5 or 0.5
hope it helps !