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svet-max [94.6K]
3 years ago
11

Winston owns a coffee cart. He charges $3.50 for a cup of coffee, and it costs him $1.50 to make each cup of coffee plus $100 a

day for other expenses. Which equation can be used to determine how many cups of coffee, c, that Winston needs to sell each day in order to break even?
Mathematics
1 answer:
jekas [21]3 years ago
6 0

Answer:

50 cups of coffee

Step-by-step explanation:

So what you do is take 3.50 then subtract 1.50 to get the profit of one cup of coffee. ($2) Then you do the $100 and divide it by the $2 and find out how many cups of coffee he has to sell to get to the $100. (50)

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A toy manufacturer wants to know how many new toys children buy each year. A sample of 1492 children was taken to study their pu
julia-pushkina [17]

By assuming the standard deviation of population 2.2 the confidence interval is 8.67 toys,8.94 toys.

Given sample size of 1492 children,99% confidence interval , sample mean of 8.8, population standard deviation=2.2.

This type of problems can be solved through z test and in z test we have to first find the z score and then p value from normal distribution table.

First we have to find the value of α which can be calculated as  under:

α=(1-0.99)/2=0.005

p=1-0.005=0.995

corresponding z value will be 2.575 for p=0.995 .

Margin of error=z*x/d

where x is mean and d is standard deviation.

M=2.575*2.2/\sqrt{1492}

=0.14

So the lower value will be x-M

=8.8-0.14

=8.66

=8.67 ( after rounding)

The upper value will be x+M

=8.8+0.14

=8.94

Hence the confidence interval will be 8.67 toys and 8.94 toys.

Learn more about z test at brainly.com/question/14453510

#SPJ4

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2 years ago
Trent went skiing with his family. His mom and dad made him put on many different layers of clothing so that he would be warm wh
mafiozo [28]

I think the answer is A. conductor

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3 years ago
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Hello so as you can see i got a ton of hw :) Helpp :')
olasank [31]

Answer:

Step-by-step explanation:

A. 1.13 and B is 1.37

8 0
3 years ago
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In Exercises 5-7, find all the exact t-values for which the given statement is true,
bearhunter [10]

Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

******************************************************************************

6)\quad sin (t) = \dfrac{1}{2}

Where on the Unit Circle does   sin = \dfrac{1}{2}

<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

******************************************************************************

7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

\text{Answer: at}\  \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n

In degrees:    t = 120° + 360n  and  300° + 360n

4 0
3 years ago
Divide x^3 -3x^2 by x-2<br> . Step 1 - Fill in the missing number:
vagabundo [1.1K]

Answer:


Step-by-step explanation:

First let us write the given polynomial as in descending powers of x with 0 coefficients for missing items

F(x) = x^3-3x^2+0x+0

We have to divide this by x-2

Leading terms in the dividend and divisor are

x^3  and x

Hence quotient I term would be x^3/x=x^2

                                                   x-2) x^3-3x^2+0x+0(x^2

x^3-2x^2

Multiply x-2 by x square and write below the term and subtract

We get  

                                                   x-2) x^3-3x^2+0x+0(x^2

x^3-2x^2

                                                         ---------------

-x^2+0x

Again take the leading terms and find quotient is –x

                                                x-2) x^3-3x^2+0x+0(x^2-x

x^3-2x^2

                                                         ---------------

-x^2+0x

                                                                  -x^2-2x

Subtract to get 2x +0 as remainder.

                                                  x-2) x^3-3x^2+0x+0(x^2-x-2

x^3-2x^2

                                                         ---------------

-x^2+0x

                                                                  -x^2+2x

                                                          -------------

                                                                      -2x-0

                                                                              -2x+4

                                                             ------------------

                                                                               -4

Thus remainder is -4 and quotient is x^2-x-2


8 0
3 years ago
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