The surface area is all the areas of all the exterior faces in a 3D shape.
Doing all the possibilities, 4 * 5 * 2 , 5 * 7 * 2, 4 * 7 * 2 = total surface area
40 + 70 + 56 = 166 m^2
The answer is 2. 166 m^2
Answer:
There is significant evidence to conclude that the replacement time for streetlights under the new contractor is longer than the replacement time under the previous contractor.
Step-by-step explanation:
Given the data :
6.2 7.1 5.4 5.5 7.5 2.6 4.3 2.9 3.7 0.7 5.6 1.7
The hypothesis:
H0: μ = 3.2
H1 : μ > 3.2
n = sample size = 12
The sample mean, xbar = ΣX / n
xbar = 53.2 / 12
xbar = 4.43
Using calculator;
Sample standard deviation, s = 2.147
The test statistic :
(xbar - μ) ÷ (s/sqrt(n))
(4.43 - 3.2) ÷ (2.147/sqrt(12)
1.23 / 0.6197855
Test statistic = 1.985
The Pvalue using the Pvalue from Tscore calculator :
Tscore = 1.985 ; df = 12 - 1 = 11
Pvalue = 0.036
Since Pvalue < α ; We reject the Null
Hence, we conclude that the replacement time for streetlights under the new contractor is longer than the replacement time under the previous contractor.
To complete the 100% of (the job) washing, Roland needed 4 Hours & Sam, 3 hour,
Mind you 100% = 1
Find for each one the (job) achieved in 1 hour:
Roland achieved 1/4 & Sam 1/3 each one in 1 hour.
In one hours both will achieve 1/4+1/3 =7/12
So they will complete 7/12 (of the job) in 1 hour & for a time = t they will complete 100% (or 1) of the job, that is 1/t =7/12 & t=12/7 =1.71 hour
Answer:
H0 : ρ = 0
H1 : ρ ≠ 0
Test statistic = 1.197
Pvalue = 0.2335
There is no correlation between the two variables
Step-by-step explanation:
The null and alternative hypothesis :
H0 : No correlation exist,
H1 : Correlation exist
H0 : ρ = 0
H1 : ρ ≠ 0
Test statistic, T = r / √(1 - r²) / (n - 2)
T = 0.067 / √(1 - 0.067²) / (320 - 2)
T = 0.067 / √(0.995511 / 318)
T = 0.067 / 0.0559512
T = 1.197
The Pvalue obtained from the Rscore, at df = 320 - 2 = 318 is 0.2335
α = 5% = 0.05
The Pvalue > α ; we fail to reject the null and conclude that, there is no correlation between the two variables.