Pls answer my question it is urgent
1 answer:
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Answer:
- height: 48.6 ft
- time in air: 3.4 s
Step-by-step explanation:
A graphing calculator provides a nice answer for these questions. It shows the maximum height is 48.6 feet, and the time in air is 3.4 seconds.
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The equation can be rewritten to vertex form to find the maximum height.
h(t) = -16(t^2 -54/16t) +3 . . . . . group t-terms
h(t) = -16(t^2 -54/16t +(27/16)^2) + 3 + 27^2/16
h(t) = -16(t -27/16)^2 +48 9/16
The maximum height is 48 9/16 feet, about 48.6 feet.
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The air time is found at the value of t that makes h(t) = 0.
0 = -16(t -27/16)^2 +48 9/16
(-48 9/16)/(-16) = (t -27/16)^2 . . . . . . . subtract 48 9/16 and divide by -16
(√777 +27)/16 = t ≈ 3.4297 . . . . . square root and add 27/16
The time in air is about 3.4 seconds.
Answer:
see below
Step-by-step explanation:
The ratio of terms that are two terms apart (s4 and s6) is the square of the common ratio:
s6/s4 = r^2
r = √(8/18)
r = 2/3 . . . . . matches choices A and C
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Using the formula for the general term, we now know enough to find the first term:
sn = s1·r^(n-1)
s4 = s1·(2/3)^(4-1)
Using s4 = 18 and multiplying by (2/3)^-3, we get ...
18·(2/3)^-3 = s1 = 18·27/8
s1 = 243/4 . . . . . matches choice A
