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Semenov [28]
2 years ago
12

Melody spent 16 days traveling in South America. How many weeks and days did Melody travel in South America?

Mathematics
1 answer:
Genrish500 [490]2 years ago
4 0

Answer: 2 week and 2 days

Step-by-step explanation:

Given

Melody spent 16 days in South America

A week consists of 7 days

In 2 weeks it is, 14 days

So, 16 days is equivalent to 2 weeks and 2 days

Melody spent 2 weeks and 2 days in South America

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2/3x^2

Step-by-step explanation:

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Which statement models this situation? The time between airline arrivals must be more than 2 minutes. A. t > 2 B. t = 2 C. t
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Read 2 more answers
The number of requests for assistance received by a towing service is a Poisson process with rate θ = 4 per hour.a. Compute the
aliya0001 [1]

Answer:

a) 9.93% probability that exactly ten requests are received during a particular 2-hour period

b) 13.53% probability that they do not miss any calls for assistance

c) 2

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Poisson process with rate θ = 4 per hour.

This means that \mu = 4n, in which n is the number of hours.

a. Compute the probability that exactly ten requests are received during a particular 2-hour period.

n = 2, so \mu = 4*2 = 8

This is P(X = 10). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 10) = \frac{e^{-8}*8^{10}}{(10)!} = 0.0993

9.93% probability that exactly ten requests are received during a particular 2-hour period

b. If the operators of the towing service take a 30-min break for lunch, what is the probability that they do not miss any calls for assistance?

n = 0.5, so \mu = 4*0.5 = 2

This is P(X = 0). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353

13.53% probability that they do not miss any calls for assistance

c. How many calls would you expect during their break?

n = 0.5, so \mu = 4*0.5 = 2

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3 years ago
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Answer:

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angle 1 and angle 3 = 127.3°

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Y = -1/5x + 0.5
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