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Inga [223]
3 years ago
5

Karen Meyer owns and operates Crystal Cleaning Company. Recently, Meyer withdrew $10,000 from Crystal Cleaning, and she contribu

ted $6,000, in her name, to the American Red Cross. The contribution of the $6,000 should be recorded on the accounting records of which of the following entities? a. Crystal Cleaning and the American Red Cross b. Karen Meyer's personal records and Crystal Cleaning c. Karen Meyer's personal records and the American Red Cross d. Karen Meyer's personal records, Crystal Cleaning, and the American Red Cross
Business
1 answer:
olga nikolaevna [1]3 years ago
8 0

Answer:

c. Karen Meyer's personal records and the American Red Cross

Explanation:

Karen owns the company and withdrew $10,000. That should be recorded on the accounting records of both Karen and Crystal Cleaning Company.

She later performs a new operation. She makes a contribution of $6,000 to the American Red Cross.

Now, this contribution, this operation should be recorded on her personal records and the American Red Cross. This sum: $6,000 doesn't come from Crystal Cleaning Company as the contribution was on her name.

So, the answer is C. Karen records and the American Red Cross.

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Newberry, Inc., whose reporting currency is the U.S. dollar ($), has a subsidiary in Argentina, whose functional currency also i
Mnenie [13.5K]

Answer:

1. $46,000

2.$46,000

Explanation:

According to the scenario, computation of the given data are as follows,

Inventory price = 230,000 pesos

1. Consolidated balance sheet amount = Inventory price × Rate on November 1, 2017

= 230,000 × $0.20

= $46,000

2. Consolidated statement cost of goods sold for the year ending December 31, 2018  = Inventory price × Rate on November 1, 2017

= 230,000 × $0.20

= $46,000

3 0
3 years ago
Sandblasting equipment acquired at a cost of $40,000 has an estimated residual value of $8,000 and an estimated useful life of e
marta [7]

Answer:

a. $3,000 ; $4,000

b. $7,500 ; $8,125

Explanation:

The computation of the depreciation expense under each method is shown below:

a) Straight-line method:

= (Original cost - residual value) ÷ (useful life)

For year 1

= ($40,000 - $8,000) ÷ (8 years)

= ($32,000) ÷ (4 years)  

= $4,000

In the first year, the nine months depreciation would be charged

= $4,000 × 9 months ÷ 12 months

= $3,000

The 9 months is calculated from April 1 to December 31

In this method, the depreciation is same for all the remaining useful life

So, in year 2, the depreciation expense is $4,000

(b) Double-declining balance method:

First we have to find the depreciation rate which is shown below:

= Percentage ÷ useful life

= 100 ÷ 8

= 12.5%

So, the rate would be double i.e 25%

In year 1, the original cost is $40,000, so the depreciation expense is

= $40,000 × 25% × 9 months ÷ 12 months

= $7,500

The 9 months is calculated from April 1 to December 31

And, in year 2, the depreciation expense would be

= ($40,000 - $7,500) × 25%

= $8,125

5 0
3 years ago
If you were a manager who made sure that rewards were distributed to your employees fairly based on their performance and that e
Naily [24]

Full question:

If you were a manager who made sure that rewards were distributed to your employees fairly based on their performance and that each employee clearly understood the basis for his or her own pay, you would be using: Group of answer choices

a.equity theory.

b.Theory X.

c.motivation-hygiene theory.

d. Theory Y.

e. scientific management.

<u>Option A:</u>

If you were a manager who made sure that rewards were distributed to your employees fairly based on their performance and that each employee clearly understood the basis for his or her own pay, you would be using: equity theory.

<u>Explanation:</u>

Equity theory intends to hit an equivalence within an employee’s input and output in the workplace. If the worker can observe his or her reasonable balance it would drive to a more rich association with the administration.

Equity theory affirms that if a self recognizes an inequity among themselves and a companion, they will adjust the work they do to address the circumstances fairly in their sights.  So obtaining this fair balance assists to guarantee a stable and fruitful relationship is reached with the employee, with the overall outcome being contented, excited employees.

4 0
3 years ago
Choose the scenario(s) below where the consumer behavior is a function of an interpersonal influence. a. You purchase a new smar
Andreyy89

Answer:

Explanation: c. You buy an Audi sedan because the CEO of your company drives one.

e. You buy a ticket to a movie you’ve already seen because people you work with are going to the movie

6 0
3 years ago
Your office network has been measured to stay working an average of 2,200 hours with a standard deviation of 285 hours. What is
JulsSmile [24]

We assume here that <em>the probability for an office network to fail</em> follows a <em>normal distribution</em> with a <em>population mean of 2,200 hours</em> and a <em>population standard deviation of 285 hours</em>.

Answer:

The probability that the network will stay up for 2,800 hours before it fails is about 1.743%.

Explanation:

According to the question that the office network "has been measured to stay working an average of 2,200 hours", we can conclude that, for <em>normally distributed data</em>, at this working time, the office network has a probability of failure of 50% and a probability of being working of 50%, too.

As the office network still operates, the probability of failure increases following a normal distribution. So, for 2,800 hours of operation, we need to calculate the probability of failure for this network.

For this, we need to determine the <em>z-score</em> for the raw value of x = 2,800 hours, to later consult a <em>standard cumulative normal table </em>and find the probability associated with this z-score. To calculate it, we can use the z-score formula:

z\;score = \frac{x - \mu}{\sigma}

Where

\\ \mu\;is\;the\;population\;mean

\\ \sigma\;is\;the\;population\;standard\;deviation

And <em>x</em> is the raw score or the 2,800 hours of operation for the office network.

Thus

z = \frac{2800 - 2200}{285}

z = 2.105 \approx 2.11

Having a z = 2.11 (approximately) and consulting a <em>standard cumulative normal table, </em>we have that<em> </em>P(z<2.11) = 0.98257.

In other words, for 2,800 hours of operation for the office network, there is a probability of about 98.257% that this network <em>has failed by this time</em>.

Therefore, the probability that the network will stay up for 2,800 hours is 1 - 0.98257 = 0.01743 or about 1.743% of being working before it fails (or for only about 1.743% of the cases, the office network stays working for 2,800 hours).

The graph below has the shaded area that represents this probability.

8 0
3 years ago
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