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Andrei [34K]
3 years ago
7

A car is moving with a speed of 22 m/s. The driver then brakes, and the car comes to a halt after 6.5 s. What is the distance co

vered by the car after the driver brakes, until it comes to a stop?
Physics
2 answers:
irga5000 [103]3 years ago
8 0
Velocity = -at + c 
when t = 0, v = 22 
22= 0+c ---> c = 0 
v = -at + 22 
when t = 6.5, v = 0 
0 = -6.5a + 22 
a = 22/6.5 = 44/13 


distance = d = (-1/2)a t^2 + 22t + k 
d = (-22/13)t^2 + 22t + k 
when t = 0, d = 0, so k = 0 
Mumz [18]3 years ago
6 0
Acceleration --- (-a) 
<span>velocity = -at + c </span>
<span>when t = 0, v = 22 </span>
<span>22= 0+c ---> c = 0 </span>
<span>v = -at + 22 </span>
<span>when t = 6.5, v = 0 </span>
<span>0 = -6.5a + 22 </span>
<span>a = 22/6.5 = 44/13 </span>


<span>distance = d = (-1/2)a t^2 + 22t + k </span>
<span>d = (-22/13)t^2 + 22t + k </span>
<span>when t = 0, d = 0, so k = 0 </span>
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