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Rufina [12.5K]
2 years ago
10

I will mark you brainlist!

Physics
1 answer:
trasher [3.6K]2 years ago
5 0

Explanation:

With most of our blue planet covered by water, it's little wonder that, centuries ago, the oceans were believed to hide mysterious creatures including sea serpents and mermaids. Merfolk (mermaids and mermen) are, of course, the marine version of half-human, half-animal legends that have captured human imagination for ages. One source, the "Arabian Nights," described mermaids as having "moon faces and hair like a woman's but their hands and feet were in their bellies and they had tails like fishes."

C.J.S. Thompson, a former curator at the Royal College of Surgeons of England, notes in his book "The Mystery and Lore of Monsters" that "Traditions concerning creatures half-human and half-fish in form have existed for thousands of years, and the Babylonian deity Era or Oannes, the Fish-god ... is usually depicted as having a bearded head with a crown and a body like a man, but from the waist downwards he has the shape of a fish." Greek mythology contains stories of the god Triton, the merman messenger of the sea, and several modern religions including Hinduism and Candomble (an Afro-Brazilian belief) worship mermaid goddesses to this day.

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When measurements are close to their true values, they are said to be
katovenus [111]

Answer:

When measurements are close to true

value they are called to be accurate

Explanation:

3 0
2 years ago
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A motorist traveling with a constant 15m/s passes a school crossing conner where the speed limit is 10m/s,just as a motorist pas
aleksklad [387]

Answer:

The answer is 5 seconds;

Explanation:

<h3>a) We know that the speed(V) is 15 m/s and acc. (a) is 3 m/s^2 </h3><h3>b) The formula for the acceleration is  a=\frac{V}{t};</h3><h3>Using this formula we can define the next equation:</h3><h3>3 =  \frac{15}{t} , where  t is the sought time. After solving the equation we get that t is 5; </h3><h3> </h3><h3></h3><h3></h3>
3 0
2 years ago
The energy of motion is called
liubo4ka [24]
<span>A. kinetic energy. </span>

Friction converts kinetic energy into heat, and so it represents a net loss of mechanical energy. When surfaces in contact move relative to each other, the friction between the two surfaces converts kinetic energy into heat. As demonstrated by the use of friction created by rubbing pieces of wood together to start a fire, kinetic energy is converted to heat whenever motion with friction occurs. The friction produced by brake pads in a car must generate a quantity of heat equal to the kinetic energy of the car and as a result, the brakes get quite hot.
5 0
3 years ago
Read 2 more answers
A wheel of radius 0.38 m rotates in a clockwise sense about a fixed axle with negligible friction at an initial angular speed of
andrew-mc [135]

Answer:

ωf = 2.19 rad/s

Explanation:

Newton's second law:

F = ma has the equivalent for rotation:

τ = I * α   Formula  (1)

where:

τ : It is the torque applied to the body.  (Nxm)

I :  it is the moment of inertia of the body with respect to the axis of rotation (kg*m²)

α : It is angular acceleration. (rad/s²)

Data

F = 24 N  : Tangential force

m : 14 kg : mass of the wheel

R = 0.38 m : radius of the wheel

Moment  of inertia of  the wheel

The moment of inertia of wheel is defined as follows:

I = m* R²

I = 14 kg*(0.38)²

I = 2.0216 kg*m²

Torque applied to the wheel

The Torque ( τ) applied to the wheel is defined as follows:

τ = F*d

Where:

F : Tangential force applied to the wheel

d : Perpendicular distance of the tangential force to the axis of rotation

τ = (24N)*(0.38 m)

τ = 9.12 N*m

Angular acceleration of the wheel  (α )

We replace data in the formula (1):

τ = I * α

9.12 = (2.0216) * α

α= 9.12 / (2.0216)

α = 4.5 rad/s²  

Kinematics of the wheel

We apply the equations of circular motion uniformly accelerated :  

ωf = ω₀ + α*t Formula (2)

Where:  

α : Angular acceleration (rad/s²)  

ω₀ : Initial angular speed ( rad/s)  

ωf : Final angular speed ( rad

t : time interval (s)

Data  

α = 4.5 rad/s²  

ω₀ =1.6 rad/s

t =  0.13 s    

We replace data in the formula (2):  

ωf = ω₀ + α*t

ωf = 1.6 + (4.5)*(0.13)

ωf = 1.6 + (4.5)*(0.13)

ωf = 2.19 rad/s

6 0
3 years ago
A rope connects boat A to boat B. Boat A starts from rest and accelerates to a speed of 9.5 m/s in a time t = 47 s. The mass of
Contact [7]

Answer: 339.148N

Explanation:

Data

Time (t) = 47s

U = 0m/s

V = 9.5m/s

Mass of B = 540kg

Frictional force on B = 230N

Both boats are connected so if A moves, B moves too.

Acceleration of boat A =?

Using equation of motion,

V = u + at

9.5 = 0 + a*47

a = 9.5 / 47

a = 0.2021 m/s²

The force required to accelerate boat B since it's the same force moving both boats =?

F = Mass * acceleration

F = 540 * 0.2021 = 109.14N

A frictional force of 230N exists on boat B

Total force (Tension) = frictional force + normal force = (109.15 + 230)N = 339.148N

7 0
2 years ago
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