Question

A race car starts from rest on a circular track of radius 310 m. Its speed increases at the constant rate of 0.6 m/s 2 . At the point where the magnitudes of the radial and tangential accelerations are equal, determine the speed of the race car. Answer in units of m/s

Answer 1

Answer:

The speed of the race car is 13.63 m/s.

Explanation:

It is given that,

Radius of the circular track, r = 310 m

Acceleration of the car, $v = 0.6\ m/s^2$

We need to find the speed of the race car. In circular motion, the object moves under the action of centripetal acceleration which is given by :

$a=\dfrac{v^2}{r}$

$v=\sqrt{a\times r}$

$v=\sqrt{0.6\times 310}$

v = 13.63 m/s

So, the speed of the race car is 13.63 m/s. Hence, this is the required solution.