A 2.43ug particle moves at 1.97 x 108 m/s. What is its momentum?

Physics

1 answer:

Ira Lisetskai [31]3 years ago

4 0

Answer:

0.48 kgm/s

Explanation:

$m$ = mass of the particle = 2.43 μg = 2.43 x 10⁻⁶ x 10⁻³ kg = 2.43 x 10⁻⁹ kg

$v$ = velocity of the particle = 1.97 x 10⁸ m/s

$p$ = momentum of the particle

momentum of the particle is given as

$p = m v$

inserting the values

$p = (2.43\times 10^{-9})(1.97\times 10^{8})$

$p = 0.48$ kgm/s

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