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alexgriva [62]
3 years ago
13

How many endpoints does a ray have?

Mathematics
2 answers:
Tresset [83]3 years ago
7 0
A Ray has 1 endpoint
xxMikexx [17]3 years ago
5 0
A ray has only one end point 

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Which expression is equivalent to (m^5n/pq^2)^4
tatuchka [14]
\left( \cfrac{m^5n}{pq^2}\right)^4 =  \cfrac{(m^5n)^4}{(pq^2)^4}=  \cfrac{m^{20}n^4}{p^4q^8}
8 0
3 years ago
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I really need help tyy
emmainna [20.7K]
Find the greatest common factor (gcf) in each grade between the girls and boys
in 6th grade the gcf is 8
64/8=8  72/8=9
the largest number of groups that can be made equally would be 8 groups of 8 girls and 8 boys
Hope this helps!!
6 0
3 years ago
Write an equation of the line passing through the points (4,6) and (-2, - 18).
olga_2 [115]

Answer:

y = 4x – 10

Step-by-step explanation:

slope formula: m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }

point-slope formula: y-y_{1}=m\left(x-x_{1}\right)

  1. Use slope formula and plug in your numbers: m = \frac{-18-6}{-2-4 }
  2. Solve for slope m = 4
  3. Use the point-slope formula to solve for the equation: y-6=4\left(x-4\right)
  4. Solve and find equation: y=4x-10

Note: When given two points you only need to pick one for the point-slope formula! Best to choose the positive one so you don't have to deal with the negatives!

Hope this helps! Please give Brainliest!

4 0
2 years ago
A music store buys instruments and then sells them for 30% more than they paid.
seropon [69]

Answer:135.2

Step-by-step explanation:

5 0
3 years ago
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Mr. Harrow has eight boys and six girls in his Honors Pre-calculus class. If he randomly chooses two students, one at a time, wh
Sergeu [11.5K]

Answer: 15/91 which is choice B

=================================================================

There are two methods to find this answer.

Method 1) We have 6 girls and 8+6 = 14 students. The probability of picking a girl is 6/14 = 3/7. After the first girl is chosen, we have 5 girls left out of 14-1 = 13 students overall. The probability of picking another girl (assuming the first selection was a girl) is 5/13. Multiply these probabilities: (3/7)*(5/13) = (3*5)/(7*13) = 15/91

--------------------

Method 2) We can use the nCr combination formula. Order does not matter.

We have nCr = 6 C 2 = 15 ways to pick 2 girls. See the attached image below for the steps (figure 1)

Out of nCr = 14 C 2 = 91 ways to pick 2 students. See the attached image below for the steps (figure 2)

So that's another way to get the answer 15/91.

5 0
3 years ago
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