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3 years ago

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Consider the equations: f(x)= -6x-1 and g(x) = 4x^2 Select the solution for (f+g) (x).

2 answers:

11111nata11111 [884]3 years ago

8 0

$f(x)=-6x-1 \\ g(x)=4x^2 \\ \\ So \ : \\\boxed{ (f+g)(x)=4x^2-6x-1}$

<em>Please mark as best! =)</em>

MAXImum [283]3 years ago

8 0

$(f+g)(x)=f(x)+g(x)\\
(f+g)(x)=-6x-1+4x^2=4x^2-6x-1$

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Need help with 2,3,4

Harman [31]

Answers:

In these exercices are ilustrated the representations of the fractions

2) Firstly, we have 3 equal segments, each one representing $\frac{1}{4}$ , hence:

$\frac{3}{4}$ is <u>3</u> copies of $\frac{1}{4}$

Let's prove it, taking into account we are adding fractions with the same denominator:

$\frac{1}{4}+\frac{1}{4}+\frac{1}{4}=\frac{3}{4}$

There are <u>4</u> equal parts that make a whole

Four copies of <u> $\frac{1}{4}$ </u> make $\frac{4}{4}$ or <u>1</u> whole

$\frac{1}{4}+\frac{1}{4}+\frac{1}{4}+\frac{1}{4}=\frac{4}{4}=1$

3) Here we have a line divided into four segments, each one of $\frac{1}{5}$ . Hence:

This is $\frac{4}{5}$ of a line. $\frac{4}{5}$ is <u>4</u> lengths of $\frac{1}{5}$

$\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}=\frac{4}{5}$

If we draw one more $\frac{1}{5}$ we will have $\frac{5}{5}$ or 1 whole.

Then:

<u>5</u> lengths of $\frac{1}{5}$ make $\frac{5}{5}$ or <u>1</u> whole.

4) In this part the answer is in the attached image. If we have two equal segments, each one of $\frac{1}{3}$ we will have as a result $\frac{2}{3}$ .

If we add another $\frac{1}{3}$ segment, we will have three segments of $\frac{1}{3}$ , having as a result $\frac{3}{3}=1$

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3 years ago

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cricket20 [7]

There are 16 cups in a gallon. 6 pints in a quart. 4 quarts in a gallon.

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A roulette wheel has 38 3838 slots, of which 18 1818 are red, 18 1818 are black, and 2 22 are green. In each round of the game,

Elina [12.6K]

The value of P(R = 3) is 0.2854

<h3>Probability</h3>

Probabilities are used to determine the chances of events.

The given parameters are:

$n = 38$ --- the number of slots
$red = 18$ . --- the number of red slot
$black = 18$ . --- the number of black slot
$green = 2$ . --- the number of green slot

<h3>Individual probabilities</h3>

The probability that the ball lands on a red slot is calculated as:

$p = \frac{18}{38}$

Simplify

$p= \frac{9}{19}$

The probability that the ball does not land on a red slot is calculated as:

$q = \frac{18+2}{38}$

$q = \frac{20}{38}$

Simplify

$q = \frac{10}{19}$

<h3>Binomial probability</h3>

The value of P(R = 3) is then calculated using the following binomial probability formula

$P(R = r) = ^nC_rp^rq^{n-r}$

Where:

$n = 7$

$r = 3$

So, we have:

$P(R = 3) = ^7C_3 \times (9/19)^3 \times (10/19)^{7-3}$

$P(R = 3) = 35 \times (9/19)^3 \times (10/19)^4$

$P(R = 3) = 0.2854$

Hence, the value of P(R = 3) is 0.2854

Read more about probabilities at:

brainly.com/question/15246027

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