Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
One as it intersects only on the Y axis
Hello.
In order to solve a proportion, you should cross-multiply:
Multiply 7 times 9 and 5 times x:
5x=63
Divide both sides by 5:
x=
Now let's solve the second proportion.
Multiply 8p times 6 and 12 times 15:
48p=180
Divide both sides by 48:
p=3.75
I hope it helps.
Have an outstanding day.
Answer:
y = -13x+26
Step-by-step explanation:
13x+y=26
y= -13x+26
Answer:
108
Step-by-step explanation:
Since 18 x 2 = 36 you can just multiply 54 x 2. 54 x 2 =108
