Answer:
Step-by-step explanation:
Let the base camp is point A and boats' locations after two hours are points B and C.
By connecting the three points together we get a triangle ABC with sides:
- AB = 50*2 = 100 km
- AC = 70*2 = 140 km
The angle between AB and AC is:
- 60 + 50 = 110 degrees (opposite directions from south)
We are looking for the distance BC, which can be found by using the law of cosines:
- BC² = AB² + AC² - 2AB*AC*cos ∠BAC
- BC² = 100² + 140² - 2*100*140*cos 110°
- BC² = 39176.56 (rounded)
- BC = √39176.56 = 197.93 km (rounded)
The distance between the boats is 197.93 km.
I'm going to assume you mean:
13 * (3/4) + x = 7 * (1/4)
Let's go ahead and simplify the right side.
7 * (1/4) = 1.75
So now we have:
13 * (3/4) + x = 1.75
Now let's take care of the right side. Multiplication before addition.
13 * (3/4) = 9.75
9.75 + x = 1.75
To isolate x, we subtract 9.75 from both sides.
9.75 - 9.75 + x = 1.75 - 9.75
x = -8
Hopefully I spaced this well. \('-')/
Answer:
(-1, 4)
Step-by-step explanation:
Point B is 5 units below point A, and point E is 5 units above point D: AB = ED. This means that BC will be equal to EF. B and C are 7 units apart, so 7 units left from E is (-1, 4).
Hope this helps!
Just squish the two equations into one equation and idk im just typing this because i apparently need a twenty character long answer
