Question

If the endpoints of the diameter of a circle are (8, 6) and (2,0), what is the standard form equation of the circle?

Answer 1

Answer:

It is C.

Step-by-step explanation:

The centre of the circle is at the midpoint of The diameter = (8+2)/2, (6+0)/2 = (5,3) so the left side of the equation is (x-5)^2+(Y-3)^2. Now we need to work out the radius:

The diameter = square root(8-2)^2+6^2) = square root of 72 = 6sqrt2.

So the radius = 3sqrt2 and r^2=18.