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3 years ago

If the endpoints of the diameter of a circle are (8, 6) and (2,0), what is the standard form equation of the circle?

Mathematics

1 answer:

zvonat [6]3 years ago

3 0

Answer:

It is C.

Step-by-step explanation:

The centre of the circle is at the midpoint of The diameter = (8+2)/2, (6+0)/2 = (5,3) so the left side of the equation is (x-5)^2+(Y-3)^2. Now we need to work out the radius:

The diameter = square root(8-2)^2+6^2) = square root of 72 = 6sqrt2.

So the radius = 3sqrt2 and r^2=18.

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3 years ago

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2 years ago

Read 2 more answers

In exercises 1 and 2, Find the value of x.

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From the given picture, we can see that 2 sides are congruen, then the given triangle is an isosceles triangle. In this triangle the base angles are congruent, so we can draw the following picture:

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