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neonofarm [45]
3 years ago
5

Solve the cube root of x^2-8=2

Mathematics
2 answers:
zalisa [80]3 years ago
8 0

Answer:

x= \sqrt10 - \sqrt10

Step-by-step explanation:

koban [17]3 years ago
5 0

Answer:

x= -4 or x= 4

Step-by-step explanation:

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Find the fifth term An=n/n+1
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Read 2 more answers
A company takes out an insurance policy to cover accidents that occur at its manufacturing plant. The probability that one or mo
yKpoI14uk [10]

Answer:

0.289792.

Step-by-step explanation:

If we define a month with one or more accident as "success"; and

A month with no accident as "failure" .

  • P(one or more accidents will occur during any given month)=0.60.
  • P(no accident will occur during any given month)=1-0.60=0.40

We want to calculate the probability that there will be at least four months in which no accidents occur before the fourth month in which at least one accident occurs.

in this case, let k=number of failures before the fourth success

Therefore, k\geq 4

k follows a negative binomial distribution.

Therefore, the probability is:

P(k\geq 4)=1-P(k\leq 3)\\=1-\sum_{k=0}^{3}\left(\begin{array}{ccc}3+k\\k\end{array}\right)(0.60)^4(0.40)^k\\=1-(0.60)^4 \left[\left(\begin{array}{ccc}3\\0\end{array}\right)(0.40)^0+\left(\begin{array}{ccc}4\\1\end{array}\right)(0.40)^1+\left(\begin{array}{ccc}5\\2\end{array}\right)(0.40)^2+\left(\begin{array}{ccc}6\\3\end{array}\right)(0.40)^3\right]\\=1-(0.60)^4 \left[ 1+1.6+1.6+1.28\right]\\=1-(0.60)^4[5.48]\\=0.289792

The required probability is 0.289792.

4 0
3 years ago
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