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Ganezh [65]
1 year ago
6

ILL GIVE BRAINIEST

Mathematics
1 answer:
katovenus [111]1 year ago
5 0

Answer:

Step-by-step explanation:

<h2>7 but th 3rd is silrt</h2>
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Can you help me pls ?
Leno4ka [110]

Answer:

More than 1/2.

Step-by-step explanation:

1/2 in decimal form is 0.5, and since 0.7 is greater than 0.5, that means it is greater than 1/2.

7 0
2 years ago
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Find the value of x that makes this statement true
Brrunno [24]
\frac{(-2)^{5x-3}}{(-2)^{2x}} =(-2)^{21}

(-2)^{5x-3-2x}=(-2)^{21}  (The numerator and the denominator has same bases, therefore the powers will get subtracted. It is an exponential property)

(-2)^{3x-3}=(-2)^{21}

3x-3=21  (As the left hand side is equal to right hand side and the bases are on both the sides are equal too, we will equate their exponential power. Another property)

x-1=7

x=8  (After simplifying more, you'll get this)
4 0
3 years ago
Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for
nevsk [136]

Answer:168

Step-by-step explanation:   First you do 82 times 3.75 which is 307.50. Then you do 2071.5 - 307.5 = 1764 Then you do 1764 divided by 10.50 which is 168

9 0
3 years ago
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A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
What are the measures of the two angles in the figure below?
Mumz [18]

Answer: answer is A. 80 degrees and 100 degree

Step-by-step explanation:

4 0
3 years ago
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