To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors.
<span>Define projection of v on u as </span>
<span>p(u,v)=u*(u.v)/(u.u) </span>
<span>we need to proceed and determine u1...u5 as: </span>
<span>u1=w1 </span>
<span>u2=w2-p(u1,w2) </span>
<span>u3=w3-p(u1,w3)-p(u2,w3) </span>
<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
<span>u5=w5-p(u4,w5)-p(u2,w5)-p(u3,w5)-p(u4,w5) </span>
<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>
<span>However, the given set of vectors is not independent, since </span>
<span>w1+w2=w3, </span>
<span>therefore an orthogonal basis cannot be found. </span>
Answer:
We conclude that the machine is under filling the bags.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 436.0 gram
Sample mean, 
= 429.0 grams
Sample size, n = 40
Alpha, α = 0.05
Population standard deviation, σ = 23.0 grams
First, we design the null and the alternate hypothesis
We use one-tailed(left) z test to perform this hypothesis.
Formula:
Putting all the values, we have
Now, 
Since,
We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.
Since the left side of the equation says f(5), then plug in 5 for x.
So, it is:
-4|5| + 3
= -20 + 3
= 23
