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olasank [31]
3 years ago
13

Please help.............

Mathematics
2 answers:
natta225 [31]3 years ago
6 0

Answer:

...........

2(x + 2) + 2x = 20

Amiraneli [1.4K]3 years ago
6 0

Answer:

x(x+2) = 20

Step-by-step explanation:

Perimeter Formulas of rectangle is: Perimeter = 2 × (a + b)

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The illustration below shows the graph of y as a function of x.
zloy xaker [14]

Answer:

x = 18

Step-by-step explanation:

5 0
3 years ago
Solve for x<br> (-4/3) x - 6 = -26<br><br> A. −27<br> B. −15<br> C. 15<br> D. 27
andre [41]
- \dfrac{4}{3} x - 6 = -26

//Add 6 to both sides:
- \dfrac{4}{3} x  = -20

//Multiply by -1 on both sides:
\dfrac{4}{3} x  = 20

Multiply by 3 on both sides:
4x  = 60

Divide by 4 on both sides:
x  = 15

-----------------------------------------
Answer: x = 15 (Answer C)
-----------------------------------------
5 0
3 years ago
Read 2 more answers
The principal of a high school spent 1700 for X desk each and Y chairs at $25 each if he had bought half the number of desk in t
KatRina [158]

Answer:

25X + 25Y = 1700

25X + 100Y = 3200

Step-by-step explanation:

Given that the principal of a high school spent $1700 for X desk and Y chairs at $25 each. Then, the equation will be

25X + 25Y = 1700 ....... (1)

If he had bought half the number of desk in twice the number of chairs he would have spent 1600. That is

25(X/2) + 25(2Y) = 1600

25X/2 + 50Y = 1600

Find the LCM and cross multiply

25X + 100Y = 3200 ........(2)

6 0
3 years ago
What is m3 + 9n when m = 4 and n = 5
WINSTONCH [101]
I believe the answer is 57
6 0
3 years ago
Read 2 more answers
Describe lengths of three segments that could not be used to form a triangle. Segments with lengths of 5 in., 5 in., and ______
Vesna [10]

Answer:

c = 11

Step-by-step explanation:

Given

Let the three sides be a, b and c

Such that:

a = b= 5

Required

Find c such that a, b and c do not form a triangle

To do this, we make use of the following triangle inequality theorem

a + b > c

a + c > b

b + c > a

To get a valid triangle, the above inequalities must be true.

To get an invalid triangle, at least one must not be true.

Substitute: a = b= 5

5 + 5 > c ===> 10 > c

5 + c > 5  ===> c > 5 - 5 ===> c > 0

5 + c > 5  ===> c > 5 - 5 ===> c > 0

The results of the inequality is: 10 > c and c > 0

Rewrite as: c > 0 and c < 10

0 < c < 10

This means that, the values of c that make a valid triangle are 1 to 9 (inclusive)

Any value outside this range, cannot form a triangle

So, we can say:

c = 11, since no options are given

8 0
3 years ago
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