I need help figuring out this question

Which number line represents the solution to -3x ≤ -36?

seraphim [82]

Answer:

x ≥12

Step-by-step explanation:

-3x ≤ -36

Divide each side by -3, remembering to flip the inequality

-3x/-3 ≥ -36/-3

x ≥12

4 0

3 years ago

Morgan, Dakota and Taylor showed their work solving the equation 7x+5x+1=73. Identify the student with the invalid first step an

antoniya [11.8K]

Answer:

Step-by-step explanation:

Given the equation solved by Morgan, Dakota and Taylor expressed as 7x+5x+1=73, to get the value of x, the valid steps are as shown;

7x+5x+1=73

take the sum of 7x and 5x

12x+ 1 = 73

subtract 1 from both sides

12x+1-1 = 73-1

12x = 72

Divide both sides by 12

12x/12 = 72/12

x = 6

Based on the calculation above, the students with invalid first step is Dakota.

<em>Dakota added 5x with 1 to get 6x which is an invalid step because 1 is not attached to a variable x. A function cannot be added to a constant hence making his first step invalid.</em>

8 0

3 years ago

Read 2 more answers

Plsss help ill give brainiest

Elena L [17]

To solve this problem, we have to use the area of both gauze or the dimensions on each gauze and compare them. we can see that the sheets are not similar as they have different areas.

<h3>Area of Rectangle</h3>

The area of a rectangle is given as the product between the length and it's width.

Data;

Length = 9in
Area = 45in^2
width = ?
length 2 = 4in
width 2 = 3in

$area = length * width$

In the first gauze, the area is given as 45in^2 and we have value of the length. To find the width of the first gauze can be calculated as

$A = length * width\\width = \frac{area}{length} \\width = \frac{45}{9} \\width = 5in$

We can see that the width are not equal so is their length.

But if we would truly compare them, the accurate way to do that is by their area

The area of the second gauze is given by

$a = 3 * 4 = 12in^2$

From the above calculations, we can see that the sheets are not similar as they have different areas.

Learn more on area of a rectangle here;

brainly.com/question/25292087

3 0

1 year ago

Sin (x/2)= √2- sin (x/2) solve for the exact solutions in the interval (0, 2π)

serg [7]

$sin\left( \frac{x}{2} \right)=\sqrt{2}-sin\left( \frac{x}{2} \right)\implies sin\left( \frac{x}{2} \right)+sin\left( \frac{x}{2} \right)=\sqrt{2}\implies 2sin\left( \frac{x}{2} \right)=\sqrt{2} \\\\\\ sin\left( \cfrac{x}{2} \right)=\cfrac{\sqrt{2}}{2}\implies sin^{-1}\left[ sin\left( \cfrac{x}{2} \right) \right]=sin^{-1}\left( \cfrac{\sqrt{2}}{2} \right) \implies \cfrac{x}{2}= \begin{cases} \frac{\pi }{4}\\\\ \frac{3\pi }{4} \end{cases} \\\\[-0.35em] ~\dotfill$