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Aleksandr-060686 [28]
3 years ago
15

You are trying to find the impulse of an object through experimentation

Physics
1 answer:
alexira [117]3 years ago
7 0

Answer:

Impulse is given by

Force × Time

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Two identical 0.50-kg carts, each 0.10 m long, are at rest on a low-friction track and are connected by a spring that is initial
Keith_Richards [23]

Answer:

The system's kinetic energy changes by 3.6 J

Explanation:

The given parameters are;

The number of cart = 2

The mass of each cart = 0.5kg

The initial length of the spring = 0.50 m

The final length of the spring =T0.3 m

The change in position of the first cart = 0.6 m

The energy given to the first cart = Work done by the force = Force × Displacement

The initial kinetic energy of the two cart moving together = Energy given to the first cart = 6.0 × 0.2 = 1.2J

The kinetic energy given to the two cart combined = The applied force × The total displacement of the two cart as they move together

The kinetic energy given to the two cart combined = 6.0 × (0.6 - 0.2)

The kinetic energy given to the two cart combined = 6.0 × 0.4 = 2.4 J

The total kinetic energy given to the two cart = 1.2 + 2.4 = 3.6 J

The total kinetic energy given to the two cart = 3.6 J

The system's kinetic energy changes by 3.6 J.

8 0
3 years ago
Ron bicycles forward with an acceleration of 2.1 m/s2. If he is applying a forward force
Mila [183]

Answer:

195

Explanation:

he can only apply as much force as his body  mass so it would be 195

3 0
3 years ago
Why are less massive stars thought to age more slowly than more massive stars have much less fuel?
docker41 [41]
The reason being nuclear reactions are slow in less massive stars than in massive stars hence they age slowly.
8 0
4 years ago
A ball is launched straight up with initial speed of 30.0 m/s. What is the ball's velocity when it comes back to its original po
Zanzabum

Answer:

We could get the time taken by the ball to return back to earth, using the formula:

s = u t + ½ a t², where

s = displacement of the body moving with initial velocity u, acceleration 'a' in time t.

In the present case s=0 (as the ball returns back to starting time)

u= 30 m/s; a = -10 m/s² ( negative sign as a is in opposite direction to u); t=?

0 = 30 t - ½ ×10 ×t²; ==> 5 t = 30, t= 6 second.

So ball will return back after 6 second after being thrown up.

Explanation:

I looked it up

Hope this helps

3 0
3 years ago
Plz help
Nikolay [14]

The answer to this is C

7 0
4 years ago
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