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seraphim [82]
4 years ago
7

Plz help

Physics
1 answer:
Nikolay [14]4 years ago
7 0

The answer to this is C

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Why does the moon appear to wax grow larger and then wane or get smaller
Umnica [9.8K]
When the moon is waxing it means that the sunlit fraction we can see from earth is getting larger. when it is wanning, the sunlit fraction is getting smaller and even as the phases of the moon change the total amount of sunlight the moon gets remains the same. half the moon is always in sunlight just as half the earth is always in sunlight. but because the period of rotation for the moon is the same as its period of revolution, on earth we always see the same side of the moon. If you lived on the far side of the moon, you would see the sun for half of each lunar day, but you would never see the earth.
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3 years ago
What happens to the particles of matter vibrated by a wave after the wave passes through the matter
Mariulka [41]

Answer:

As they vibrate, they pass the energy of the disturbance to the particles next to them, which pass the energy to the particles next to them, and so on.

Explanation:

5 0
3 years ago
An electron in the beam of a TV picture tube is accelerated through a potential difference of 2.00 kv.?It then passes into a mag
Stells [14]

Answer:

The magnitude of the field is 8.384×10^-4 T.

Explanation:

Now, i start solving this question:

First, convert the potential difference(V) 2 kv to 2000 v.

As, we have the final formula is qvB = mv^2/r. It came from the centripetal force and the magnetic force and we know that these two forces are equal. When dealing with centripetal motion use the radius and not the diameter so

r = 0.36/2 = 0.18 m.

As, we are dealing with an electron so we know its mass is 9.11*10^-31 kg and its charge (q) is 1.6*10^-18 C.

We can solve for its electric potential energy by using ΔU = qV and we know potential energy initial is equal to kinetic energy final so ΔU = ΔKE and kinetic energy is equal to 1/2mv^2 J.

qV = 1/2mv^2

(1.6*10^-19C)(2000V) = (1/2)(9.11*10^-31kg) v^2

v = 2.65×10^7 m/s.

These all above steps we have done only for velocity(v) because in the final formula we have 'v' in it. So, now we substitute the all values in that formula and will find out the magnitude of the field:

qvB = mv^2/r

qB = mv/r

B = mv/qr

B = (9.11*10^-31 kg)(2.65×10^7 m/s) / (1.6*10^-19 C)(0.18 m)

Hence, B = 8.384*10^-4 T.

5 0
3 years ago
if a cyclist is travelling a road due east at 12km/h and a wind is blowing from south-west at 5km/h. find the velocity of the wi
slamgirl [31]

Answer:

The velocity of wind with respect to cyclist is -15.5 \widehat{i} - 3.5 \widehat{j}.

Explanation:

speed of cyclist = 12 km/h east

speed of wind = 5 km/h south west

Write the speeds in the vector form

\overrightarrow{vc} = 12 \widehat{i}\\\\overrightarrow{vw} = - 5 (cos 45 \widehat{i} + sin 45 \widehat{j})\\\\\overrightarrow{vw} =-3.5 \widehat{i} - 3.5 \widehat{j}

The velocity of wind with respect to cyclist is

\overrightarrow{vw} =-3.5 \widehat{i} - 3.5 \widehat{j}\overrightarrow{v_(w/c)} = \overrightarrow{vw}-\overrightarrow{vc}\\\\\overrightarrow{v_(w/c)} = - 3.5 \widehat{i} - 3.5 \widehat{j}  - 12 \widehat{i}\\\\\overrightarrow{v_(w/c)} =-15.5 \widehat{i} - 3.5 \widehat{j}

7 0
3 years ago
How many pounds must a sandbag weigh to test if a safety net can absorb the proper amount of force
inessss [21]
I believe its 400lbs
3 0
3 years ago
Read 2 more answers
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