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liq [111]
3 years ago
8

What type of energy do you observe from a light bulb

Physics
1 answer:
Lunna [17]3 years ago
3 0
Potential if it is off or kinetic energy when its on
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What is vertical displacement
nataly862011 [7]
Distance in the y direction.
5 0
3 years ago
Read 2 more answers
A conducting spherical shell with inner radius a and outer radius b has a positive point charge +Q at the center in the empty re
Andreas93 [3]

Answer:

a) q_inner = -Q

, q_outer = -2Q

b)    E₁ = k Q / r²        r<a

       E₂ = 0               a<r<b

       E₃ = - k 2Q/r²     r>b

d)   the charge continues inside the spherical shell, the results do not change

Explanation:

a) The point load in the center induces a load on the inner surface of the shell with constant opposite sign  

q_inner = -Q  

the outer shell of the shell the load is  

q_outer = -3 Q + Q  

q_outer = -2Q

b) To find the electric field again, use Gauss's law,  

We define as a Gaussian surface a sphere  

Ф = E. dA = q_{int}/ε₀

in this case the electric field lines and the radii of the sphere are parallel, so the sclar product is reduced to the algegraic product  

E A = q_{int}/ε₀

the area of ​​a sphere is  

A = 4 π r²  

E = 1 / 4πε₀  Q/ r²  

k = 1 / 4πε₀  

let's apply this expression to the different radii

i) r <a  

in this case the load inside is the point load  

q_{int}= + Q  

E₁ = k Q / r²

ii) the field inside the shell  

a <r <b  

As the sphere is conductive, so that it is in electrostatic equilibrium, there can be no field within it.  

E₂ = 0

iii)  r>b

   q_{int}  = Q- 3Q = -2Q

    E₃ = k (-2Q/r²)

     E₃ = - k 2Q/r²

c) see  attached

d) as the charge continues inside the spherical shell, the results do not change, since the lcharge inside remains the same and it does not matter its precise location, but remains within the Gaussian surface

6 0
3 years ago
A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connec
Wewaii [24]

Answer:

Velocity = 0.4762 m/s

Explanation:

Given the details for the simple harmonic motion from the question as:

Angular frequency, ω = 12 rad/s

Amplitude, A = 0.060 m

Displacement, y = 0.045 m

The initial Energy =  U  = (1/2) kA²    

where A is the amplitude and k is the spring constant.

The final energy is potential and kinetic energy

   K + U =   (1/2) mv²   + (1/2) kx²  

where  x  is the displacement

m is the mass of the object

v is the speed of the object

Since energy is conservative. So, the final and initial energies are equal  as:

   (1/2) k A²   = (1/2) m v²   + (1/2) kx²  

Using,   ω² = k/m, we get:  

Velocity:

v=\omega\times \sqrt{[ A^2 - y^2 ]}

v=\omega\times \sqrt{[ {0.06}^2 - {0.045}^2 ]}

<u>Velocity = 0.4762 m/s</u>

4 0
3 years ago
Can someone please help me !!<br><br> What is the mass of a mosquito in grams?
Vlad [161]

Serious answer: The average mosquito masses 1-2 mg. Even the state birds of Minnesota. Amazing, considering the nuisance they cause.

Sure hope this helps

5 0
2 years ago
Explain Newtons Second Law of motion in terms of momentum.
Marat540 [252]

Answer:

the net external force equals the change in momentum of a system divided by the time over which it changes. The change in momentum is the difference between the final and initial values of momentum.

Explanation:

i hope it will help

3 0
3 years ago
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