I would need to have the same book and go to page 73 to be able to answer it. By the way, do you have any friends that have the answer?
278. I got It By Counting The Letters On Meh Keyboard As Many Times As The #'s On My Keyboard.
(a) The probability of drawing a blue marble at random from a given box is the number of blue marbles divided by the total number of marbles. We assume that the probability of selecting one of two boxes at random is 1/2 for each box.
... P(blue) = P(blue | box1)·P(box1) + P(blue | box2)·P(box2) = (3/8)·(1/2) + (4/6)·(1/2)
... P(blue) = 25/48 . . . . probability the ball is blue
(b) P(box1 | blue) = P(blue & box1)/P(blue) = (P(blue | box1)·P(box1)/P(blue)
... = ((3/8)·(1/2))/(25/48)
... P(box1 | blue) = 9/25 . . . . probability a blue ball is from box 1
I believe you haven't included the system of equations for us to solve.
However, I will tell you that you need to solve for one variable in an equation and substitute that into the other equation.
For example:
x = yz; z = x/y
a = zb; a = (x/y)b
Hope this helps!
Answer:
Step-by-step explanation:
m∠1 = 2x and m∠2 = -3x+235
angle 1 and angle 2 are supplementary angle so they add up to 180°
m∠1 +m∠2 = 180°
2x -3x+235 = 180°
-x = 180-235
x=35
m∠1 = 2x = 2*35 = 70°
m∠2 = -3x+235 = -3*35 +235 = 235-105 = 130°
