The equations are based on the following assumptions
1) The bar is straight and of uniform section
2) The material of the bar is has uniform properties.
3) The only loading is the applied torque which is applied normal to the axis of the bar.
4) The bar is stressed within its elastic limit.
Nomenclature
T = torque (Nm)
l = length of bar (m)
J = Polar moment of inertia.(Circular Sections) ( m^4)
J' = Polar moment of inertia.(Non circluar sections) ( m^4 )
K = Factor replacing J for non-circular sections.( m^4)
r = radial distance of point from center of section (m)
ro = radius of section OD (m)
τ = shear stress (N/m^2)
G Modulus of rigidity (N/m^2)
θ = angle of twist (radians)
Answer:
Technicians A is right for the answer
Answer You ask your coach
Answer:
To help wheels move in a circle
Explanation:
Answer:

Explanation:
From the question we are told that:
Initial Pressure 
Initial Temperature 
Final Pressure 
Final Temperature 
Work Output 
Generally Specific Energy from table is
At initial state


With
Specific Volume 
At Final state


Generally the equation for The Process is mathematically given by

Assuming Mass to be Equal

Where



Therefore

