Answer:
438.4$ each month
Explanation:
you get this answer by dividing the total payment by the months
Answer:
Option B Lower than
Explanation:
Gauge pressure is a relative measurement based on atmospheric pressure. Gauge pressure can be positive if it is above atmospheric pressure or it can also be negative it is below. On another hand, absolute pressure is an actual pressure in a space and its value has always to be zero or above. Basically absolute pressure is zero if it is in a perfect vacuum. So the measurement of absolute pressure is gauge pressure + atmospheric pressure. This is the reason in normal condition the gauge pressure = absolute pressure - atmospheric pressure and therefore is lower than absolute pressure
Answer:
B-as deadly storms that claim lives in th great pines
Explanation:
I hope it helped if it did pls make me brainliest
Answer:
both technologies offer a cleaner alternative to internal combustion engines, and both use electric motors powered by electrochemical device.
Answer:
The correct answers are:
a. % w = 33.3%
b. mass of water = 45g
Explanation:
First, let us define the parameters in the question:
void ratio e =
= 
Specific gravity
=

% Saturation S =
×
=
× 
water content w =
=
a) To calculate the lower and upper limits of water content:
when S = 100%, it means that the soil is fully saturated and this will give the upper limit of water content.
when S < 100%, the soil is partially saturated, and this will give the lower limit of water content.
Note; S = 0% means that the soil is perfectly dry. Hence, when s = 1 will give the lowest limit of water content.
To get the relationship between water content and saturation, we will manipulate the equations above;
w = 
Recall; mass = Density × volume
w = 
From eqn. (2)
= 
∴ 
putting eqn. (6) into (5)
w = 
Again, from eqn (1)

substituting into eqn. (7)

∴ 
With eqn. (7), we can calculate
upper limit of water content
when S = 100% = 1
Given, 
∴
∴ %w = 33.3%
Lower limit of water content
when S = 1% = 0.01

∴ % w = 0.33%
b) Calculating mass of water in 100 cm³ sample of soil (
)
Given,
, S = 50% = 0.5
%S =
×
=
× 
0.50 = 
mass of water = 