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The coefficient of static friction is the ratio of the maximum static friction force (F) between the surfaces in contact before movement commences to the normal (N) force.
<h3>What is coefficient of static friction formula?</h3>
- The friction coefficient is the ratio of the normal force pushing two surfaces together to the frictional force preventing motion between them.
- Typically, it is represented by the Greek letter mu (). In terms of math, is equal to F/N, where F stands for frictional force and N for normal force.
- The ratio of the greatest static friction force (F) between the surfaces in contact before movement starts to the normal force (N) is known as the coefficient of static friction.
- A body and a surface have static and kinetic friction coefficients of 0.75 and 0.5, respectively. The body is forced to slide with a constant acceleration that is equal to A. g4 by applying a force.
Find the attachment answer.
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Answer:
Option B Lower than
Explanation:
Gauge pressure is a relative measurement based on atmospheric pressure. Gauge pressure can be positive if it is above atmospheric pressure or it can also be negative it is below. On another hand, absolute pressure is an actual pressure in a space and its value has always to be zero or above. Basically absolute pressure is zero if it is in a perfect vacuum. So the measurement of absolute pressure is gauge pressure + atmospheric pressure. This is the reason in normal condition the gauge pressure = absolute pressure - atmospheric pressure and therefore is lower than absolute pressure
Answer:
the minimum component thickness for which the condition of plane strain is valid is 0.005377 m or 5.38 mm
Explanation:
Given the data in the question;
yield strength σ
= 690 Mpa
plane strain fracture toughness K
= 32 MPa-
minimum component thickness for which the condition of plane strain is valid = ?
Now, for plane strain conditions, the minimum thickness required is expressed as;
t ≥ 2.5( K
/ σ
)²
so we substitute our values into the formula
t ≥ 2.5( 32 / 690 )²
t ≥ 2.5( 0.0463768 )²
t ≥ 2.5 × 0.0021508
t ≥ 0.005377 m or 5.38 mm
Therefore, the minimum component thickness for which the condition of plane strain is valid is 0.005377 m or 5.38 mm
i believe the correct answer is c but i’m sorry if i’m not correct