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Afina-wow [57]
3 years ago
14

Determine the constant rate of change for each table.

Mathematics
1 answer:
MariettaO [177]3 years ago
4 0
Minus three every time would be the rate of change. 
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Suppose your class sells gift wrap for $4 per package and greeting cards for $10 per package. Your class sells 205 packages in a
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Answer:


Step-by-step explanation:

1,084 divided by

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3 years ago
The nutrition supervisor for a school district is considering adding a baked potato bar to the lunch for all the high school caf
Nimfa-mama [501]

Using the confidence interval, it is found that the correct option is:

There is convincing evidence because the entire interval is above 0.

<h3>When does a confidence interval for the difference of proportions gives convincing evidence that there is a difference?</h3>

It gives convincing evidence when 0 is not part of the confidence interval.

In this problem, the interval is (0.02, 0.38), which does not contain 0, hence the correct option is:

There is convincing evidence because the entire interval is above 0.

More can be learned about confidence intervals at brainly.com/question/25890103

3 0
2 years ago
The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re
PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic  clarithromycin is eliminated from the body according to the formula:

A(t) = 500e^{-0.1386t}                 ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

100= 500e^{-0.1386t}

Divide both sides by 500 we get;

\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}

Simplify:

\frac{1}{5} = e^{-0.1386t}

Taking logarithm both sides with base e, then we have;

\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})

\log_e (\frac{1}{5})=-0.1386t         [ Using \log_e e^a =a ]

or

\log_e (0.2)=-0.1386t

-1.6094379124341 = -0.1386t

 [using value of \log_e (0.2) = -1.6094379124341 ]

then;

t = \frac{-1.6094379124341}{-0.1386}

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams


6 0
3 years ago
The scores on a quiz are normally distributed. The mean of the quiz is 93 and the standard deviation is 4.2. By using the Empiri
xz_007 [3.2K]

Answer:

any score that lies between 88.8 and 97.2 is within one std. dev. of the mean

Step-by-step explanation:

One std. dev. above the mean would be 93 + 4.2, or 97.2.  One std. dev. below the mean would be 93 - 4.2, or 88.8.

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Factor as the product of two binomials x^2-2x+1
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Answer:(x + 1)^2

Step-by-step explanation:

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