A, B and C are collinear and B is in the middle.
so we have AB + BC =AC
6x +x-5= 23
7x -5=23
adding 5 to both sides
7x=23+5
7x =28
dividing both sides by 7
we get x=28/7 =4
So answer is x=4
I did the math and I think it should be 67.5
Answer:
The probability of of a randomly chosen student being exactly 21 years old.
= 1.293
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given Population size n = 500</em>
<em>Mean of the Population = 20 years and 6 months</em>
<em> = </em><em></em>
<em>Standard deviation of the Population = 2 years</em>
Let 'X' be the range of ages of the students on campus follows a normal distribution
Let x =21
<em>The probability of a randomly chosen student being exactly 21 years old.</em>
<em>P( Z≤21) = 0.5 + A( 0.2) </em>
= 0.5 +0.793
= 1.293