Given that the height of the ball has been modeled by h=120t-16t^2, the reasonable range will be found as follows:
maximum height is attained when h'(t)=0
given h=120t-16t^2
h'(t)=120-32t=0
thus solving for t, we get:
t=3.75 sec
thus the maximum time attained will be:
120(3.75)-16(3.75)^2=225 ft
Therefore the reasonable range will be [0≤h(t)≤225]
Answer:
x² + 7x + 12
Step-by-step explanation:
1. (x +3)(x+4) - Distribute
2. x² + 4x +3x + 12 - Add like terms
3. x² +7x + 12
Answer:
125
Step-by-step explanation:
5x5x5
7.49, 7.5%, 749/50 hope it help