Answer:
its LSA is 4800m^2.
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Answer:
Total eclipse was
minutes longer than in 2005.
Step-by-step explanation:
It is given in the question that total eclipse in 2003 lasted
minutes and in 2005 it lasted 3/8 of a minute.
We have to calculate how much longer did it last in 2003.
So we have to subtract the duration in 2003 by duration in 2005
Total time taken in 2003- total time taken in 2005





minutes
Answer:
p = ½ (x₁ + x₂)
q = a (x₁x₂ − ¼ (x₁ + x₂)²)
Step-by-step explanation:
y = a (x − x₁) (x − x₂)
Expand:
y = a (x² − x₁x − x₂x + x₁x₂)
y = a (x² − (x₁ + x₂)x + x₁x₂)
Distribute a to the first two terms:
y = a (x² − (x₁ + x₂)x) + ax₁x₂
Complete the square:
y = a (x² − (x₁ + x₂)x + ¼(x₁ + x₂)²) + ax₁x₂ − ¼ a(x₁ + x₂)²
y = a (x − ½ (x₁ + x₂))² + a (x₁x₂ − ¼ (x₁ + x₂)²)
Therefore:
p = ½ (x₁ + x₂)
q = a (x₁x₂ − ¼ (x₁ + x₂)²)
Answer:
978 in^2
Step-by-step explanation:
the area of the rectangle:
24in X 30in = 720 in^2
the area of the two similar triangles:
12 X 9 / 2 + 12 X 9 / 2 = 108 in^2
the area of the last triangle:
20 in X 15 in /2 = 150in^2
.
the total area is the sum of the areas:
720in^2 + 108in^2 + 150in^2 = 978in^2.