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enyata [817]
3 years ago
9

Please help me for 3, 4, and 5 please

Mathematics
1 answer:
almond37 [142]3 years ago
3 0

Answer:

Step-by-step explanation:

3: Possible outcomes for a coin flip; heads tails

Total possible outcomes for two coin flips 2*2=4

Out the 4 possible outcomes only 1 of them both times it land on heads

1/4

4: and 5 i dont know

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Please help this is important<br> -1.5x+12=2.5x-12
Anna35 [415]

Answer:

x = 6

Step-by-step explanation:

move all terms to the left:

-1.5x+12-(2.5x-12)=0

get rid of parentheses

-1.5x-2.5x+12+12=0

add all the numbers together, and all the variable.

-4x+24=0

move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4 - divide

x=+6

7 0
3 years ago
500=100(x-1)<br> Someone tell me step by step
Andre45 [30]
First, distribute the 100 to the (x-1) portion:
500 = 100x - 100

then, add 100 to both sides of your equation to get “x” alone on the right side:
500 + 100 = 100x - 100 + 100
600 = 100x

next, divide 100x by 100 and 600 by 100 to isolate a singular “x”:
600/100 = 100x/100
6 = x

therefore, x=6 is your solution
5 0
2 years ago
A ride at a theme park lasts on and one half minutes.it takes 2 minutes to prepare the ride for each trip how many times can the
nlexa [21]
1 time=2mins
xtimes=30mins

30/2 ×1= 15.
Therefore it can be completed 15 times in 30mins
6 0
3 years ago
Read 2 more answers
A first play of football game resulted in a loss of 12.5 yards. Then a penalty resulted in another loss of 5 yards. What is the
lions [1.4K]
The total loss is 17.5 yards.
8 0
3 years ago
1000 households were surveyed. 275 households own a desktop computer, 455 households own a DVD player, 405 households own two ca
icang [17]

Answer:

Step-by-step explanation:

From the given information,

Suppose

X represents the Desktop computer

Y represents the DVD Player

Z represents the Two Cars

Given that:

n(X)=275

n(Y)=455

n(Z)=405

n(XUY)=145

n(YUZ)=195

n(XUZ)=110

n((XUYUZ))=265

n(X ∩ Y ∩ Z) = 1000-265

n(X ∩ Y ∩ Z) = 735

n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)

145 = 275+455 - n(X ∩ Y)

n(X ∩ Y) = 585

n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)

195 = 455+405-n(Y ∩ Z)

n(Y ∩ Z) = 665

n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)

110 = 275+405-n(X ∩ Z)

n(X ∩ Z) = 570

a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)

n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735

n(X ∪ Y ∪ Z) = 50

c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)

n(X ∪ Y ∪ C') = 145-50

n(X ∪ Y ∪ C') = 95

6 0
3 years ago
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