When you simplify the expression 1/1+cot^2x the final product is C. sin^2 (x).
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Let the number of large bookcases be x and number of small bookcases be y, then
Maximise P = 80x + 50y;
subkect to:
6x + 2y ≤ 24
x, y ≥ 2
The corner points are (2, 2), (2, 6), (3.333, 2)
For (2, 2): P = 80(2) + 50(2) = 160 + 100 = 260
For (2, 6): P = 80(2) + 50(6) = 160 + 300 = 460
For (3.333, 2): P = 80(3.333) + 50(2) = 266.67 + 100 = 366.67
Therefore, for maximum profit, he should produce 2 large bookcases and 6 small bookcases.
Answer:
1 
Step-by-step explanation:
5/3 = 3/3 * 2/3
3/3 = 1
So the answer is 1
Answer:
b=12
Step-by-step explanation:
3b +24= b +48
-24 -24
3b = b+ 24
-b -b
2b = 24
÷2 ÷2
b=12
Answer: A 1 to 4
Step-by-step explanation:
