Answer:
![5565](https://tex.z-dn.net/?f=5565)
Step-by-step explanation:
![1+2+3+4...+113+114=\frac{114*115}{2} =6555](https://tex.z-dn.net/?f=1%2B2%2B3%2B4...%2B113%2B114%3D%5Cfrac%7B114%2A115%7D%7B2%7D%20%3D6555)
![1+2+3+4 ... +43+44=\frac{44*45}{2} =990](https://tex.z-dn.net/?f=1%2B2%2B3%2B4%20...%20%2B43%2B44%3D%5Cfrac%7B44%2A45%7D%7B2%7D%20%3D990)
Thus,
![6555-990=5565](https://tex.z-dn.net/?f=6555-990%3D5565)
Answer:
3
Step-by-step explanation:
<h3><u>Answer</u><u>:</u><u>-</u></h3>
x=17
<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>
![{\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}](https://tex.z-dn.net/?f=%7B%5Cboxed%7B%5Cquad%5C%3A%5Cmapsto%5Crm%20Firstly%5C%3ALet%27s%5C%3Aunderstand%5C%3Athe%5C%3Aconcept%3A-%7D%7D)
<h3 />
This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.
<h3><u>Solution</u><u>:</u><u>-</u></h3>
Given angles
According to sum theory
![{\boxed{\sf The \:sum\:of\:angles=180°}}](https://tex.z-dn.net/?f=%7B%5Cboxed%7B%5Csf%20The%20%5C%3Asum%5C%3Aof%5C%3Aangles%3D180%C2%B0%7D%7D)
![\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180](https://tex.z-dn.net/?f=%5Cqquad%20%5Cquad%7B%3A%7D%5Clongmapsto%5Ctt%20%286x%2B10%29%2B%28x%2B17%29%2B%284x-34%29%3D180%20)
![\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180](https://tex.z-dn.net/?f=%5Cqquad%20%5Cquad%7B%3A%7D%5Clongmapsto%5Ctt%206x%2B10%2Bx%2B17%2B4x-34%3D180%20)
- Together like polynomials and constants
![\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180](https://tex.z-dn.net/?f=%5Cqquad%20%5Cquad%7B%3A%7D%5Clongmapsto%5Ctt%206x%2Bx%2B4x%2B10%2B17-34%3D180%20)
![\qquad \quad{:}\longmapsto\tt 11x-7=180](https://tex.z-dn.net/?f=%5Cqquad%20%5Cquad%7B%3A%7D%5Clongmapsto%5Ctt%2011x-7%3D180%20)
![\qquad \quad{:}\longmapsto\tt 11x=180+7](https://tex.z-dn.net/?f=%5Cqquad%20%5Cquad%7B%3A%7D%5Clongmapsto%5Ctt%2011x%3D180%2B7%20)
![\qquad \quad{:}\longmapsto\tt 11x=187](https://tex.z-dn.net/?f=%5Cqquad%20%5Cquad%7B%3A%7D%5Clongmapsto%5Ctt%2011x%3D187%20)
![\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}](https://tex.z-dn.net/?f=%5Cqquad%20%5Cquad%7B%3A%7D%5Clongmapsto%5Ctt%20x%3D%5Ccancel%7B%5Cdfrac%7B187%7D%7B11%7D%7D)
![\qquad \quad{:}\longmapsto\tt x=17](https://tex.z-dn.net/?f=%5Cqquad%20%5Cquad%7B%3A%7D%5Clongmapsto%5Ctt%20x%3D17)
![\therefore\sf The \:value\:of\:x\;is\:17.](https://tex.z-dn.net/?f=%5Ctherefore%5Csf%20The%20%5C%3Avalue%5C%3Aof%5C%3Ax%5C%3Bis%5C%3A17.)
Y=-13/2x+43/2 I hope this helped :3