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3 years ago

What Is the place value of 8 in 5678

1 answer:

6 0

That would be the ones place, because 7 would be the tens place, 6 would be the hundreds place, and 5 would be the thousands place.
Hope this helped >.<

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Which numbers are factors of 29? Select all that apply. 5 9 1 21

Tamiku [17]

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Factors are values that the number can be divided by to produce an integer (whole number)

Simply test them out:

29/5 = 5.8

29/9 = 3.2

29/1 = 29

29/21 = 1.38....

As per the statement above, the only factor of 29 from this line is 1.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0

3 years ago

Which of the following is the correct sl unit to use in measuring amount of material contained in a solid sphere

ruslelena [56]

Volume would be the correct sl unit to use in measuring amount of material contained in a solid sphere... Hope this helps

7 0

3 years ago

Popcorn was donated for the school fair by 3 different popcorn vendors. They donated a total of 996 bags of popcorn. Each vendor

Marysya12 [62]

Answer:

let the of bag of vendors be X

3donate X bag to give 996

3×x=996

3x=996

divide both side by 3

3x\3=996\3

x=332

each vendor donated 332bags of popcorn

5 0

3 years ago

Read 2 more answers

The mass of the eggs laid by a certain breed of hen is a normally distributed random variable with mean 0.06kg and standard devi

Olin [163]

a (i) The number of standard size is 288 eggs

a (ii) The number of medium size is 1,476 eggs

a (iii) The number of large size is 36 eggs

b (i) The expected profit made from selling the standard size is Gh¢43.2

b (ii) The expected profit made from selling the medium size is Gh¢516.6

b (iii) The expected profit made from selling the large size is Gh¢16.2

The given parameters:

the mean of the distribution, m = 0.06 kg

standard deviation (std) of the distribution, d = 0.009 kg

number of the samples, n = 1800 eggs

(i) Find the position of "less than 0.052 kg (standard size)":

1 standard deviation below the mean = m - d

m - d = 0.06 kg - 0.009 kg = 0.051 kg

(the standard size is 1 standard deviation below the mean)

less than 1 standard deviation below the mean in a normal distribution is equal to 16% of the data samples

Number of standard size = 0.16 x 1800 = 288 eggs

(ii) Find the position of "Between 0.052 kg and 0.075kg (medium size)":

0.052 kg is 1 standard deviation below the mean

2 standard deviation above the mean = m + 2d
m + 2d = 0.06 + 2(0.009) = 0.078 kg

(the medium size is between 1 std below the mean and 2 std above the mean)

Between 1 std below the mean and 2 std above the mean in a normal distribution = (68 + 14)% = 82%

Number of medium size = 0.82 x 1800 = 1,476 eggs

(iii) Find the position of "Greater than 0.075 kg (large size)":

0.078 kg is 2 standard deviation below the mean
greater than 2 std above the mean in a normal distribution = 2 % of the data samples
Number of large size = 0.02 x 1800 = 36 eggs

Check: 288 eggs + 1476 eggs + 36 eggs = 1,800 eggs

(b) the cost of production of an egg = Gh¢0.45

the selling price of the standard size = Gh¢0.60

the selling price of the medium size = Gh¢0.80

the selling price of the large size = Gh¢0.95

(i) The expected profit made from selling the standard size:

Profit = total revenue - cost of production

Profit = 288(0.6) - 288(0.45) = Gh¢43.2

(ii) The expected profit made from selling the medium size:

Profit = total revenue - cost of production

Profit = 1476(0.8) - 1476(0.45) = Gh¢516.6

(iii) The expected profit made from selling the large size: