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Mrac [35]
3 years ago
10

Solve for x: 8x2 + 64x = 0

Mathematics
2 answers:
ikadub [295]3 years ago
6 0
8x2+64x=0

16x+64x=0 ===> x=0
Svet_ta [14]3 years ago
4 0
8 x² + 64 x = 0
x · ( 8 x + 64 ) = 0
x = 0,  or:  8 x + 64 = 0
                 8 x = - 64
                 x = - 64 : 8
                 x = - 8
Answer :  x = 0, or x = -8
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A rectangle with length n and height m. A right triangle with hypotenuse n + 1, length n, and height m.
Oksana_A [137]

9514 1404 393

Answer:

  C. 12cm

Step-by-step explanation:

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__

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  m^2 +n^2 = (n+1)^2

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  289 -34n +n^2 +n^2 = n^2 +2n +1 . . . . eliminate parentheses

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8 0
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goblinko [34]

Answer:

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Step-by-step explanation

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we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

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therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
3 years ago
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