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mr Goodwill [35]
3 years ago
8

The long handle on a rake is a _____.

Physics
1 answer:
artcher [175]3 years ago
6 0
From what i know it is c. it is a lever
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Consider 2 steel rods, A and B, B has three times the area and twice the length of A, so young modulus of B will be what factor
AVprozaik [17]

Answer:

  \frac{Y}{Y_o} = 2/3

Explanation:

The yuong modulus of a rod is defined as the relationship between the tensile strength and the strain

         Y =  \frac{ \frac{F}{A} }{\frac{\Delta L}{L_o} }

let's use the subscript "o" for rod A

         I = \frac{ \frac{F}{A_o} }{ \frac{\Delta L}{L_o} }

tells us that rod B has

         A = 3 A₀

         L = 2 L₀

we substitute

         Y = \frac{ \frac{F}{A} }{ \frac{\Delta L}{L} }

          Y = \frac{ \frac{F}{3A_o} }{ \frac{\Delta L}{ 2L_o}  }

         y = ⅔  \frac{ \frac{F}{A_o}}{ \frac{\Delta }{L_o} }

substituting the value of Y₀

          Y = ⅔  Y₀

           \frac{Y}{Y_o} = 2/3

5 0
3 years ago
A neighbor's child wants to go to a neighborhood carnival to experience the wild rides. The neighbor is worried about safety as
seraphim [82]

Answer:

No, the ride is not safe

Explanation:

From the diagram attached, it is seen that

\sum f_{y} = 0

\tau cos \theta - W = 0................(1)

\sum f_{x} = 0

-ma + \tau sin \theta = 0.......(2)

a = w^{2} r

From the diagram, r = Lsin \theta

a = w^{2} L sin \theta

w = \frac{2\pi }{T}

a = \frac{4\pi ^{2}L sin \theta }{T^{2} }............(3)

Put (3) into (2)

\tau sin \theta = \frac{4\pi ^{2}m L sin \theta }{T^{2} }

\tau  = \frac{4\pi ^{2}m L  }{T^{2} }

w = weight of chair + weight of child = 50 + 10 = 60 lb

g = 32 ft/s²

m = w/g = 60/32 = 1.875

L = 30 ft

T = 3 secs

\tau  = \frac{4\pi ^{2}*1.875*30  }{0.3^{2} }

\tau = 246.74 lbs

since 246.74 lbs > 200 lbs, it is not safe because the stationary chair will creak

6 0
3 years ago
Read 2 more answers
An automobile moves at a constant speed over the crest of a hill traveling at a speed of 88.5 km/h. At the top of the hill, a pa
Sergio039 [100]

Answer:

r=61.65m

Explanation:

Since the package remains in contact with the car's seat, the package's speed is equal to the car's speed. At the top on the mountain the package's centripetal force must be equal to its weight:

mg=F_c

The centripetal force is defined as:

F_c=ma_c=\frac{mv^2}{r}

Here v is the linear speed of the object and r is the radius of curvature. We need to convert the linear speed to \frac{m}{s}:

88.5\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=24.58\frac{m}{s}

Now, we calculate r:

mg=\frac{mv^2}{r}\\r=\frac{v^2}{g}\\r=\frac{(24.58\frac{m}{s})^2}{9.8\frac{m}{s^2}}\\\\r=61.65m

3 0
2 years ago
Which are properties of both a gas and a plasma? Check all that apply.
wlad13 [49]
<span>The answer is  4, 6 and 7. Gas and plasma share most similar properties. The difference lies in the fact that plasma is composed of ions and electrons (ionized  gas) as opposed to gas that is composed of neutral molecules. Therefore plasma can conduct electricity while gas cannot. </span>




7 0
3 years ago
Read 2 more answers
If you push a 200 kg box with a horizontal force of 1,172 N and kinetic friction resists the motion with a force of 962 N, what
Lynna [10]

Answer:

a = 1.05m.s²

Explanation:

Fnet = m×a

Fapplied - friction = m×a

1172 - 962 = 200 × a

210 = 200a

a = 1.05

5 0
1 year ago
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