The can occupy similar volumes but they vary greatly in DENSITY.
Hope this helps.
Answer:
Explanation:
Electric field at the surface of the the lead 208 = KQ/ R²
where K = 8.99 × 10⁹ Nm² /C²
Q ( total charge inside the nucleus) and e is the charge of a proton = Ne = 82 × 1.6 × 10⁻¹⁹ C = 1.312 × 10⁻¹⁷ C
V of the lead = 208 v of a proton assuming they both are sphere
4/3 πR³ =208( 4/3 πr³) where R is the radius of the sphere and r is the radius of the proton
R³ = 208 r³
R = ∛( 208 r³) = 5.92r
replace r with 1.20 x 10-15 m
R = 5.92 ×1.20 x 10-15 m = 7.11 × 10⁻¹⁵ m
E = ( 8.99 × 10⁹ Nm² /C² × 1.312 × 10⁻¹⁷ C ) / (7.11 × 10⁻¹⁵ m)² = 0.233 × 10²² N/C = 2.33 × 10²¹ N/C
Force = mass x acceleration
25N = 0.40kg x acceleration
25N/0.40kg = acceleration
acceleration = 62.5 N/kg
N/kg is the equivalent of m/s²
So your acceleration is 62.5 meters per second squared
Answer:62.5 J
Explanation:
Given
Inductance(L)=5 H
resistance(R)
Voltage(V)=100 V
Current in L-R circuit is given by
![I=I_0\left [ 1-e^{-\frac{Rt}{L}}\right ]](https://tex.z-dn.net/?f=I%3DI_0%5Cleft%20%5B%201-e%5E%7B-%5Cfrac%7BRt%7D%7BL%7D%7D%5Cright%20%5D)
and Power=i^2R+Li\frac{di}{dt}[/tex]
For Steady state i.e. at
Energy Stored is 
C. is the answer to this question
