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tatuchka [14]
3 years ago
12

Which car has the most kinetic energy?

Physics
1 answer:
Andru [333]3 years ago
8 0
50kg driving at 30kph because it’s the heaviest yet fastest!
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When light in vacuum is incident at the polarizing angle (Brewster's angle) on a certain glass slab, the angle of refraction is
marysya [2.9K]

Answer:

Explanation:

θ( p ) + θ( r ) = 90  

θ (r) = angle of refraction and θ ( p ) is polarising angle.

given θ ( r ) = 31.8

θ ( p ) = 90 - 31.8 = 58.2 degree

ii ) Tanθ ( p ) = n ( refractive index ) = Tan 58.2 = 1.6

3 0
3 years ago
PLEASE HELP ANSWER FAST As the vibration of molecules decreases, the _____ of the substance decreases. 1.temperature 2.internal
Aleksandr [31]
I think 1 and 3 is absolutely right but im not sure about number 2.
I think the answer is 4 all of the above because as the vibration decrease automatically the kinetic energy decrease and the temperature is decrease because when the vibration of molecules decrease thats mean the substances is slightly become a solid and you can get a solid cube of liquid if you freeze them
8 0
3 years ago
An object on Earth weighs 150 N. What is its mass?
Alex777 [14]

Answer:

\tt \: mass \:  =  \frac{weight}{acceleration \: due \: to \: gravity}

\longrightarrow \tt \:  \frac{150}{10}

\longrightarrow \boxed{ \tt{15 \: kg}}

  • Our final answer is 15 kg .

----------- HappY LearninG<3 ------------

3 0
2 years ago
Near the end of a marathon race, the first two runners are separated by a distance of 45.6 m. The front runner has a velocity of
morpeh [17]

Answer:17.08 s

Explanation:

Given

distance between First and second Runner is 45.6 m

speed of first runner(v_1)=3.1 m/s

speed of second runner(v_2)=4.65 m/s

Distance between first runner and finish line is 250 m

Second runner need to run a distance of 250+45.6=295.6 m

Time required by second runner t=\frac{295.6}{4.65}=63.56 s

time required by first runner to reach finish line=\frac{250}{3.1}=80.64 s

Thus second runner reach the finish line 80.64-63.56=17.08 s earlier

3 0
4 years ago
How much mass energy could be obtained from the complete conversion of a 235 g hamburger?
Radda [10]
E = mc²
E = 0.235 kg · (3×10⁸ m/s)² = 0.235 · 9×10¹⁶  kg·m/s²
E = 2.115×10¹⁶ J
The answer is d) 2.12×10¹⁶ J
8 0
3 years ago
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