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3 years ago

6

Which of the following statements about radioactive decay is true?

2 answers:

Strike441 [17]3 years ago

6 0

First Question is B.

Second Question is D.

yawa3891 [41]3 years ago

4 0

"<span>During radioactive decay, atoms break down, releasing, particles or energy" is the one statement about radioactive decay among the following choices given in the question that is true. The correct option is option "b".

"H</span>alf-life" is the term among the following that <span>refers to the time it takes for one-half of the radioactive atoms in a sample of a radioactive element to decay. The correct option is option "d".</span>

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A car traveling at 27.4 m/s hits a bridge abutment. A passenger in the car, who has a mass of 65.0 kg, moves forward a distance

Minchanka [31]

Answer:

$F=43570.9N$

Explanation:

We can calculate the acceleration experimented by the passenger using the formula $v_f^2=v_i^2+2ad$ , taking the initial direction of movement as the positive direction and considering it comes to a rest:

$a=\frac{v_f^2-v_i^2}{2d}=\frac{-v_i^2}{2d}$

Then we use Newton's 2nd Law to calculate the force the passenger of mass m experimented to have this acceleration:

$F=ma=\frac{-mv_i^2}{2d}$

Which for our values is:

$F=\frac{-(65kg)(27.4m/s)^2}{2(0.56m)}=43570.9N$

6 0

3 years ago

A plot of land has been surveyed for a new housing development with borders AB, BC, DC, and DA. The plot of land is a right trap

balandron [24]

Angle ABC is 119

Length of DC is 105

6 0

3 years ago

Read 2 more answers

Amoebas have projections called pseudopods. What are they used for

Dvinal [7]

Answer:

Amoebas have projections called pseudopods

Explanation:

Pseudopodia is the locomatary organ of amoeba. It helps them in movement and transportation.

8 0

2 years ago

The pitch of a sound wave is its _________. <br> A.speed B.amplitude C.frequency D.wavelength

Artyom0805 [142]

Hi there my friend :)

Your answer is C. frequency

Hope this helps :)

-xxAnsxx-

8 0

3 years ago

A car is towing a boat on a trailer. The driver starts from rest and accelerates to a velocity of +15.2 m/s in a time of 22.3 s.

scZoUnD [109]

Answer:

The tension is 384 N.

Explanation:

To calculate the acceleration, we know the velocity and the time, so:

a=Δv/t

$a=\frac{15\frac{m}{s} }{22.3s}$

$a=0.67\frac{m}{s^{2} }$

To calculate the tension we need to apply Newton's second law:

∑F=m*a

$F=573Kg *0.67\frac{m}{s^{2} }\\F=384N$

4 0

3 years ago