Answer:
yes bc it washed it away so
Explanation:
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The final velocity of the projectile when it strikes the ground below is 198.51 m/s.
<h3>
Time of motion of the projectile</h3>
The time taken for the projectile to fall to the ground is calculated as follows;
h = vt + ¹/₂gt²
where;
- h is height of the cliff
- v is velocity
- t is time of motion
265 = (185 x sin45)t + (0.5)(9.8)t²
265 = 130.8t + 4.9t²
4.9t² + 130.8t - 265 = 0
solve the quadratic equation using formula method,
t = 1.89 s
<h3>Final velocity of the projectile</h3>
vyf = vyi + gt
where;
- vyf is the final vertical velocity
- vyi is initial vertical velocity
vyf = (185 x sin45) + (9.8 x 1.89)
vyf = 149.322 m/s
vxf = vxi
where;
- vxf is the final horizontal velocity
- vxi is the initial horizontal velocity
vxf = 185 x cos(45)
vxf = 130.8 m/s
vf = √(vyf² + vxf²)
where;
- vf is the speed of the projectile when it strikes the ground below
vf = √(149.322² + 130.8²)
vf = 198.51 m/s
Learn more about final velocity here: brainly.com/question/6504879
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The bus will travel a further 20 m before coming to rest.
<h3>What is acceleration?</h3>
The term acceleration has to do with a change in velocity with time. Now we have;
u = 20 m/s
v = 10 m/s
s = 60 m
Now;
v^2 = u^2 -2as
v^2 - u^2 = -2as
(10)^2 - (20)^2 = - 2 * a * 60
a = (10)^2 - (20)^2/ - 2 * 60
a = 100 - 400/ - 2 * 60
a = 2.5 m/s^2
At that time;
v = 0 m/s
u = 20 m/s
a = 2.5 m/s^2
s = ?
Hence;
u^2 = 2as
s = u^2/2a
s = (20)^2/ 2 * 2.5
s = 400/5
s = 80 m
Hence, the bus will travel a further 20 m before coming to rest.
Learn more about acceleration:brainly.com/question/12550364
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Answer:
Explanation:
Given
Electric Field Strength ![E=4.5\times 10^{3}\ V/m](https://tex.z-dn.net/?f=E%3D4.5%5Ctimes%2010%5E%7B3%7D%5C%20V%2Fm)
Potential Difference between Plates is given by ![V=12.5\ kV](https://tex.z-dn.net/?f=V%3D12.5%5C%20kV)
In conducting plates a Potential difference exist between two plate which accelerate the charge when put between the conducting plates
The potential difference is given by
![\Delta V=Ed](https://tex.z-dn.net/?f=%5CDelta%20V%3DEd)
where E=Electric Field strength
d=distance between Plates
![d=\frac{\Delta V}{E}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B%5CDelta%20V%7D%7BE%7D)
![d=\frac{12.5\times 10^3}{4.5\times 10^{3}}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B12.5%5Ctimes%2010%5E3%7D%7B4.5%5Ctimes%2010%5E%7B3%7D%7D)
![d=2.78\ m](https://tex.z-dn.net/?f=d%3D2.78%5C%20m)