A sequence of transformations maps ∆ABC onto ∆A″B″C″. The type of transformation that maps ∆ABC onto ∆A′B′C′ is a__________
1 answer:
Refer to the figure shown below.
The transformation that maps ΔABC onto ΔA'B'C' is a reflection across the x-axis (or across the line y = 0).
When ΔA'B'C' is reflected across the line x = -2 (shown in the figure) to form ΔA"B"C", the vertex of ΔA"B"C" will have the same coordinates as B', which is (-2,-6).
The transformation that maps ΔABC onto ΔA'B'C' is a reflection across the x-axis (or across the line y = 0).
When ΔA'B'C' is reflected across the line x = -2 (shown in the figure) to form ΔA"B"C", the vertex of ΔA"B"C" will have the same coordinates as B', which is (-2,-6).
You might be interested in
Answer:
sec A= 1.01 and cot B =8.25
Step-by-step explanation:
Given :
sec A and cotB if a =8 and b=7
Now,
=
and
Therefore, answer will be sec A= 1.01 and cot B =8.25