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Murljashka [212]
4 years ago
14

Please help me thank you

Mathematics
1 answer:
Scilla [17]4 years ago
4 0

Answer:

only first equation is an identity

Step-by-step explanaition

so in the first equation it shows the word sin 2 0. this means that it is definitely an equality however tan is not

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A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.
Katen [24]

Answer:

Part A:- x +11 ft     Part B:- (4x+54)ft   part C:- x= 2ft  

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

Given that,

length and breadth of Trapdoor are (x+ \frac{1}{2} ) by 2x ft.

The Outside length of Rectangle is (x+16 ) ft.

Part A:- Total area (in square feet) of the stage can be represented by  

             x^{2} + 27x+ 176. Write an expression for the width of stage.

So,        Area of rectangle =  length \times breadth

                 x^{2} + 27x+ 176 = (x+16) \times breadth

                     Breadth = \frac{x^{2} + 27x+ 176}{x+16}

                     Breadth = x+11 ft.                       ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here,   Perimeter of Rectangle = 2(L+B)

                                                    = 2(x+16 + x +11)

                                                    = (4x + 54) ft

Part C:- The area of trapdoor is 10 ft^{2}. Find the value of x.

So,                        Area of trapdoor = 10 ft^{2}

                              (x +\frac{1}{2}) \times 2x =10 ft^{2}

                               2x^{2} +x - 10 = 0

                                  x = \frac{-1-9}{4} , \frac{-1+9}{4}

                                  x = \frac{-5}{2} , 2

Hence value of x is 2 ft             (Neglecting the negative value because                      

                                                   length cannot be negative).

Part D:-  The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So,   Length of trapdoor is (2+\frac{1}{2} ) = \frac{5}{2} ft

        breadth of trapdoor is 2\times 2 = 4ft

Now, outside length of Rectangle is = 18ft

And outside breadth of rectangle is = 13ft

Here, Area of trapdoor = \frac{5}{2} \times 4 = 10ft^{2}              ...................(2)

         Area of rectangle = 18 \times 13= 234 ft^{2}        ....................(3)

Thus comparing Equation (1) & (2) we found that

Area of rectangular stage is 20 times greater than the area of trapdoor.

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At a store, a hat has a regular price of x dollars. During sale, the price of the hat
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Answer:

x - 0.2x

Since the price of the hat is labelled = x,

The percentage discount on the hat price = 20%,

Thus, the discount = 20% of the price marked

= Twenty percent of x

=0.2 x =0.2 x

Therefore, the hat's new price = Marked price - Discount

= x- 0.2  = x

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Step-by-step explanation:

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