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Tju [1.3M]
3 years ago
7

for every 6 girls on the softball team there are 9 boys on the baseball team if there are 50 students on both teams how many are

girls
Mathematics
2 answers:
taurus [48]3 years ago
5 0
Key info-there are nine boys for every six girls on the softball team

9/6

9(3)=27. 6(3)18

18+27=45 5 more to go

if there is 50 students on each of the teams

9(5)=45
6(8)=48

As one can see,they both cannot multiply up to 50,but they round up.
djverab [1.8K]3 years ago
5 0

Let g = number of girls and b = number of boys, then:-


g + b = 50 ..........(1)


and


for every girl there is 1.5 boys so:-


b = 1.5g...........(2)


Substitute for b in equation (1):-

1.5g + g = 50

2.5g = 50

g = 20


Answer is there are 20 girls

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Step-by-step explanation:

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Round 14,456 to nearest ten
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14,460.

Step-by-step explanation:

14,456 up by 4. anything 6 or above goes up. the tenth place is the second to last number.

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3 years ago
in the three stacks of books there are 15 books, 9 books and 9 books if the books were rearranged so that the stack had the same
zepelin [54]

Answer:

<u>There would be 11 books in each stack, to have the same number.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Books in stack 1 = 15

Books in stack 2 = 9

Books in stack 3 = 9

2.  If the books were rearranged so that the stack had the same number of books how many books would be even?​

Total books = Books in stack 1 + Books in stack 2 + Books in stack 3

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33/3 = Number of books per stack to be the same

<u>Number of books per stack to be the same = 11</u>

3 0
3 years ago
If a and b are the measures of two first quadrant angles and sin a = 4/9 and sin b = 2/5 find sin(a+b).
frutty [35]

Answer:

sin(a+b)=\frac{4\sqrt{21}+2\sqrt{65}}{45}

Step-by-step explanation:

we are given

sin(a)=\frac{4}{9}

sin(b)=\frac{2}{5}

Firstly, we will draw triangle

we get

cos(a)=\frac{\sqrt{65} }{9}

cos(b)=\frac{\sqrt{21} }{5}

now, we can sue formula

sin(a+b)=sin(a)cos(b)+cos(a)sin(b)

now, we can plug values

sin(a+b)=\frac{4}{9}\times \frac{\sqrt{21} }{5}+\frac{\sqrt{65} }{9}\times \frac{2}{5}

now, we can simplify it

sin(a+b)=\frac{4\sqrt{21}+2\sqrt{65}}{45}


6 0
3 years ago
Which ordered pairs are in the solution set of the system of linear inequalities?
Anna [14]

The ordered pairs (5 , -2) , (3 , 1) , (4 , 2) are in the set of the solution (Option C)

<h3>What is an ordered pair?</h3>

An ordered pair is a composite of the x coordinate (abscissa) and the y coordinate (ordinate), with two values expressed between parenthesis in a predetermined order.

It aids visual comprehension by locating a point on the Cartesian plane.

<h3>How do we arrive at the solution?</h3>

The first line has negative slope and passing through points (0 , 0) and (4 , -2)

That is y > (-1/2)x

The second line has positive slope and passing through points (-2 , 0) and (2 , 2)

That is: y < (1/2)x + 1.

- Refer to the accompanying diagram to discover the common component of the solutions.

- The inequity is shown by the red shading.

- The inequity is shown by the blue shading.

- The two-colored shaded area reflects the common solutions to the two inequalities.

- Let's discover the ordered pairs in the system of linear inequalities' solution set.

- Points (-4, 2), (-3, 1), (4, -3) define the common shaded area.

- Points (5, -2), (3, 1), (3, -1) (4 , 2)

As a result, Point (5, -2) is in the darkened region.

As a result, Point (3, 1) is in the darkened area.

As a result, Point (4, 2) is in the darkened area.

As a result, the ordered pairings (5, -2), (3, 1), (4, 2) are in the solution set.

Learn more about ordered pair at;
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3 0
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