Andrew can jog 144 miles in 11 hours. Enter the number of miles he can jog in 1 hour.

The measure of B is (3x-4)° and the measure of D is (2x-6)°. What are the measures of angles B and D?

Ilia_Sergeevich [38]

Answer:

5x - 10

Step-by-step explanation:

→ Find the sum of the expression

3x - 4 + 2x - 6

→ Collect all the x terms

3x + 2x - 4 - 6

→ Simplify

5x - 10

3 0

1 year ago

What are the coordinates of this and radius!

LiRa [457]

-1,1 I already told u, nut

3 0

3 years ago

HELP PLEASE, Domain and range problem

pentagon [3]

Answer:

Range is number of copies produced and set of values is; 1 ≤ N ≤ 200

Domain; Cost of publishing book in dollars; set of values are; $710 ≤ N ≤ $2700

Step-by-step explanation:

Range is a set of all the possible output values in a function while domain is the set of all possible input values.

Now, the function is given as;

C = 10N + 700

Where;

C is the cost of publishing the book in dollars

N is the number of copies of books produced

Thus, the domain will be a set of N values while Range will be a set of C values.

We are told that the first printing can produce up to 200 copies of the book.

That means a maximum of 200 books and a minimum of 1.

Thus;

Range is; 1 ≤ N ≤ 200

Maximum possible cost of the 200 books is;

C = 10(200) + 700

C = $2700

Minimum cost which will be for 1 book will be;

C = 10(1) + 700

C = $710

Thus,domain is;

$710 ≤ N ≤ $2700

6 0

2 years ago

bill is in a class of 50 students. 40% of the students in the class does not take the bus to school. how many students do not ta

Mrrafil [7]

Answer:

20 students

Step-by-step explanation:

We must find 40% of 50. To do so, calculate 50 * .4 or 50 * 1/4.

4 0

3 years ago

A piece of wire 28 ft long is cut into two pieces. One piece is used to form a square, and the remaining piece is used to form a

marusya05 [52]

Answer:

Wire should be cut in two parts with the length = 15.69 ft and 12.31 ft

Step-by-step explanation:

Length of the wire = 28 ft has been cut in two pieces.

One piece is used to form a square and remaining piece to form a circle.

Let the length of the wire which forms the square is 'l' ft.

Area of the square = (side)²

Perimeter of the square = 4(side) = l

Length of one side = $\frac{l}{4}$

So, the area of the square = $\frac{l^{2}}{16}$ ft²

Now length of the remaining part = perimeter of the circle = (28 - l) ft

2πr = (28 - l)

r = $\frac{28-l}{2\pi }$

Area of the circle formed = πr²

= $\frac{\pi(28-l)^{2} }{4(\pi )^{2} }$

= $\frac{(28-l)^{2}}{4\pi }$

Combined area of the square and circle

= $\frac{l^{2}}{16}$ + $\frac{(28-l)^{2}}{4\pi }$

Now to maximize the area we will find the derivative of the area with respect to l.

$\frac{dA}{dl}=\frac{d}{dl}[\frac{l^{2}}{16}+\frac{(28-l)^{2}}{4\pi}]$

= $\frac{d}{dl}[\frac{l^{2}}{16}+\frac{(28)^{2}+l^{2}-56l }{4\pi }]$

= $\frac{2l}{16}+\frac{(2l-56)}{4\pi }$

Now equate the derivative to zero.

$\frac{2l}{16}+\frac{(2l-56)}{4\pi }$ = 0

$(2l-56)=-\frac{2l}{16}\times 4\pi$

$(2l-56)=-\frac{\pi l}{2}$

$2l+\frac{\pi l}{2}=56$

$\frac{(4l+l\pi )}{2}=56$

l(4 + π) = 112

l(4 + 3.14) = 112

l = $\frac{112}{7.14}$

l = 15.69 ft

Length of the other part = 28 - 15.69 = 12.31 ft

Therefore, wire should be cut in two parts with the length = 15.69 ft and 12.31 ft

8 0

3 years ago

Andrew can jog 144 miles in 11 hours. Enter the number of miles he can jog in 1 hour.​

Andrew can jog 144 miles in 11 hours. Enter the number of miles he can jog in 1 hour.