Twenty-one crackers contain 147 Calories. Find the unit rate in Calories per cracker.
1 answer:
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I am assuming you want to solve for m in each case
8n = -3m + 1
8(-2) = -3m + 1
-16 = -3m + 1
-3m = -17
m =
8(2) = -3m + 1
16 = -3m + 1
-3m = 15
m = -5
8(4) = -3m + 1
32 = -3m + 1
-3m = 31
m =
Answer:
It's a true solution.
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