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garik1379 [7]
2 years ago
10

The equation y=2.16x describes the weight y of x cubic pounds of pudding. Find three solutions, list them as ordered pairs and t

hen chose two and describe what they mean in terms of the problem.
Mathematics
1 answer:
loris [4]2 years ago
8 0

Answer:

(1,2.16), (2,4.32) and (3, 6.48).

The solution (1,2.16) means that 1 cubic units of pudding weighs 2.16 pounds.

The solution (2,4.32) means that 2 cubic units of pudding weighs 4.32 lbs.

Step-by-step explanation:

The equation y=2.16x describes the weight y of x cubic pounds of pudding.

The three solutions of this equation are (1,2.16), (2,4.32) and (3, 6.48).

Now, solution (1,2.16) means that 1 cubic unit of pudding weighs 2.16 pounds.

Again, solution (2,4.32) means that 2 cubic units of pudding weigh 4.32 lbs. (Answer)

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Help me please!!!!!!
Leokris [45]

Answer:

Both figures have a perimeter of 112 inches.

Step-by-step explanation:

Question 5:

You are given a 6-sided shape, but only 4 sides. To find the perimeter, you need to account for the lengths of the other two sides. As all the angles are right angles, the length of the top horizontal side is equal to the combined length of the bottom two horizontal sides. Similarly the length of the left vertical side is equal to the combined length of the right two vertical sides. Because of this, you actually don't need to find the lengths of the unknown sides to answer the question.

This means the perimeter is:

P=(31 \times 2)+(25 \times 2)\\P=62+50\\P=112

Question 6:

Exactly the same process as above. Just double the longest vertical and horizontal sides (since the sum of the corresponding shorter sides is equal). You'll notice the longest horizontal side is 31, and the longest vertical side is 25...exactly the same as the previous question.

Therefore, the perimeter will again be 112 inches.

These two questions illustrate the difference between area and perimeter. Even though the perimeter of the two shapes is the same, the area of the second shape is larger than the area of the first.

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3 years ago
What times what equal 36
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6*6=36.....................
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Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

Multiplication can be transformed into difference of squares using the rule: \sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

Do the multiplications in \sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right).

\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

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\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

\large  \boxed{\bf\frac{1}{5} = 0.2} \\

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Answer:

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Step-by-step explanation:

you multiply both equations so that you get:

x^2-2x+7x-14

and then you simplify it to:

x^2+5x-14

<em><u>If you found this helpful please give it a thanks </u></em>

<em><u>I would also appreciate it if you give me a brainliest</u></em>

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