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Degger [83]
4 years ago
15

The ideal mechanical advantage of a machine reflects the increase or decrease in force there world be without friction, it is al

ways greater than the actual mechanical advantage because all machines must overcome friction.
options:
True
False
Physics
1 answer:
brilliants [131]4 years ago
8 0

True: the ideal mechanical advantage of a machine is always greater than the actual mechanical advantage because all machines must overcome friction.

Explanation:

For a simple machine, it is possible to calculate two types of mechanical advantage:

1) The Ideal Mechanical Advantage (IMA) is given by

IMA=\frac{d_e}{d_r}

where

d_r is the resistance arm

d_e is the effort arm

The IMA gives the mechanical advantage of the machine if there are no friction forces acting on it, and if all the work in input is converted into work in output with no loss of energy

2) The Actual Mechanical Advantage (AMA) is given by

AMA=\frac{L}{E}

where

L is the load (the force in output)

E is the effort (the force in input)

The AMA gives the real mechanical advantage of the machine. For an ideal machine,

AMA=IMA

Because there is no loss of energy due to friction.

For a real machine instead,

AMA

because part of the input energy is converted into thermal energy and other forms of energy due to the presence of friction, so it is "wasted" energy.

Learn more about levers and machines:

brainly.com/question/5352966

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A 0.10-kilogram piece of modeling clay is tossed
viva [34]

a) The initial speed of the clay is 30 m/s

b) The final velocity of the block increases (40 m/s)

Explanation:

a)

We can solve this problem by using the law of conservation of momentum. In fact, in absence of external forces (=no friction), the total momentum of the clay + block system is conserved before and after the collision. Therefore, we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 0.10 kg is the mass of the clay

u_1 is the initial velocity of the clay

m_2 = 0.10 kg is the mass of the wood block

u_2 = 0 is the initial velocity of the wood block (at rest)

v = 15 m/s is the final combined velocity of the clay+block after the collision

Re-arranging the equation, we can find u_1, the speed at which the clay was tossed:

u_1 = \frac{(m_1+m_2)v-m_2 u_2}{m_1}=\frac{(0.10+0.10)(15)-0}{0.10}=30 m/s

b)

In this second case, the clay is replaced by a bouncy ball, which rebounds back after the collision, instead of sticking with the block.

In this second case, the law of conservation of momentum becomes:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2  

where

m_1 = 0.10 kg is the mass of the ball

u_1 = 30 m/s is the initial velocity of the ball

m_2 = 0.10 kg is the mass of the wood block

u_2 = 0 is the initial velocity of the wood block (at rest)

v_1 = -10 m/s is the velocity of the bouncing ball after the collision (negative because it goes backward)

v_2 is the velocity of the block after the collision

Solving for v_2, we find the final velocity of the block:

v_2 = \frac{m_1 u_1 - m_1 v_1}{m_2}=\frac{(0.10)(30)-(0.10)(-10)}{0.10}=40 m/s

As we can see, the final velocity of the block has increased. The reason for that is that, as the ball bounces back, part of the total momentum is "carried away" by the ball in the backward direction, and since the total momentum must remain constant, this means that the momentum carried by the block in the forward direction must be larger than the previous situation.

Learn more about conservation of momentum:

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7 0
4 years ago
What is a benefit of having a standard measurement system that can be used by scientists worldwide
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3 years ago
A satellite in the shape of a solid sphere of mass 1,900 kg and radius 4.6 m is spinning about an axis through its center of mas
konstantin123 [22]

Answer:

Therefore, the new rotation rate of the satellite is 6.3 rev/s.

Explanation:

The expression for conservation of the angular momentum (L) is

L_{i} = L_{f}  I_{i}\times\omega_{i} = I_{f}\times\omega_{f}

Where

I_{i}\ and \ \omega_{i} initial moment of inertia and angular velocity

I_{f}\ and \ \omega_{f} is the final moment of inertia and angular velocity

The expression of moment of inertia of the satellite (a solid sphere) is

I_{i} = \frac{2}{5}m_{s}r^{2}

Where m_{s} is the satellite mass

r is the  radus of the sphere

Substititute 1900kg for m and 4.6m for r

I_{i} = \frac{2}{5}m_{s}r^{2}\\\\ = \frac{2}{5}\times1900 kg\times (4.6 m)^{2} \\\\= 1.61 \cdot 10^{4} kgm^{2}

The final moment of inertia of the satellite about the centre of mass

I_{f} = I_{i} + 2\timesI_{x} \\\\= 1.61 \cdot 10^{4} kgm^{2} + 2\times\frac{1}{3}m_{x}l^{2}

Where m_{x} is the antenna's mass and

I is the length of the antenna

I_{f} = 1.61 \cdot 10^{4} kgm^{2} + 2\times\frac{1}{3}150.0 kg\times(6.6 m)^{2} \\\\= 2.05 \cdot 10^{4} kgm^{2}

So, the Final rotation rate of the satellite is:

I_{i}\times\omega_{i} = I_{f}\times\omega_{f} \\\\\omega_{f} = \frac{I_{i}\times\omega_{i}}{I_{f}} \\\\= \frac{1.61 \cdot 10^{4} kgm^{2}\times8.0 \frac{rev}{s}}{2.05 \cdot 10^{4} kgm^{2}} \\\\= 6.3 rev/s

Therefore, the new rotation rate of the satellite is 6.3 rev/s.

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Why do we perform stork stand test
Lemur [1.5K]

Answer:

umm  becuase it is a test and you need them

Explanation:

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3 years ago
How does density affect refraction
WINSTONCH [101]

Answer:

please give me brainlist and follow

Explanation:

The angle and wavelength at which the light enters a substance and the density of that substance determine how much the light is refracted. ... When light passes from a more dense to a less dense substance, (for example passing from water into air), the light is refracted (or bent) away from the normal.

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3 years ago
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