Answer:
The ratio of the width of the slits to the separation between them is 1:5
Explanation:
Given that:
Specific minimum for single slit = m₁ =1
Specific maximum of double slit = m₂ = 5
Formula for single slit differential minimum
here W is slit thickness, m is minimum order. For given case m=1

Formula for double slit differential maxima:

d is separation between slits, m is order for constructive interference i.e m =5.

λ is the wave length of light.
We have to find the ratio of the width of the slits to the separation between them, if the first minimum of the single-slit pattern falls on the fifth maximum of the double-slit pattern.
So dividing (1) by (2)
